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Zina [86]
3 years ago
9

You want to close an open door by throwing either a 400-g lump of clay or a 400-g rubber ball toward it. you can throw either ob

ject with the same speed, but they are different in that the rubber ball bounces off the door while the clay just sticks to the door. which projectile will apply the larger impulse to the door and be more likely to close it and why?

Physics
1 answer:
gogolik [260]3 years ago
5 0
Refer to the diagram shown below.

Let m =  the mass (g) of the door.
Let v =  the launch velocity
Let u =  the velocity of the door after impact.

Elastic impact (rubber ball):
The rubber ball bounces off the door with presumably elastic impact, which means that both momentum and kinetic energy are conserved.
Conservation of momentum requires that
400v = -400v + mu
Therefore
u=( \frac{800}{m} )v

Inelastic impact (clay):
The clay sticks to the door after impact.
Conservation of momentum requires that
400g = (m+400)u
Therefore
u=( \frac{400}{m+400} )v

When we compare magnitudes of u for the door, we find that
u_{1}=( \frac{400}{m} )(2v), \,\, elastic \\\\ u_{2}=( \frac{400}{m+400} )v , \,\, inelastic
Clearly, the elastic impact creates a greater value of u for the door.

Answer:
The rubber ball creates a larger impulse to the door because the nature of its impact is approximately elastic.


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Answer:

The dart with the small mass will travel the farthest distance.

Explanation:

Acceleration is proportional to force times mass, and inertia is proportional to mass. Inertia is the reluctance of a moving body to stop, and a stationary body to start moving (inertia increses with mass). Assuming they both have the same aerodynamic design, and that they are both launched with the same force applied for the same time duration, the dart with less small mass will accelerate faster than the big mass dart. From this we can see that the small dart will have covered a longer distance before the effect of the force stops, when compared to the more massive dart.

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3 years ago
A small metal sphere has a mass of 0.14 g and a charge of -22.0 nc . it is 10 cm directly above an identical sphere with the sam
Allushta [10]
For this problem, we use the Coulomb's law written in equation as:

F = kQ₁Q₂/d²
where
F is the electrical force
k is a constant equal to 9×10⁹ 
Q₁ and Q₂ are the charge of the two objects
d is the distance between the two objects

Substituting the values:

F = (9×10⁹)(-22×10⁻⁹ C)(-22×10⁻⁹ C)/(0.10 m)²
F = 0.0004356 N
4 0
3 years ago
Write in the word "stronger" or "weaker." The bigger and
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Answer:

weaker has the heavier of an object

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How is power defined? Question 4 options: the quantity of work accomplished the direction of the work the total distance an obje
GarryVolchara [31]

Power can be defined as the rate at which work is accomplished.

Option D is the correct answer.

<h3></h3><h3>Power </h3>

The work done by an object in a given time interval is called the power of that object.

Suppose an external force F is applied to any object for the time interval T seconds. Due to this external force, the object will perform some amount of work for the time T seconds. This work W done by the object for the time interval T seconds is called the power of that object.

Power can be defined in mathematical term which is given below.

P = \dfrac {W}{T} \;\rm Watts

Thus the power can also be defined as the work done by the object per unit time interval.

Hence we can conclude that option D is the correct answer.

To know more about power, follow the link given below.

brainly.com/question/1618040.

8 0
2 years ago
You drag a suitcase of mass 8.2 kg with a force of f at an angle 41.9 ◦ with respect to the horizontal along a surface with kine
DedPeter [7]

Answer:

35.6 N

Explanation:

We can consider only the forces acting along the horizontal direction to solve the problem.

There are two forces acting along the horizontal direction:

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F_x = F cos \theta

with \theta=41.9^{\circ}

- The frictional force, whose magnitude is

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where \mu=0.33, m=8.2 kg and g=9.8 m/s^2.

The two forces have opposite directions (because the frictional force is always opposite to the motion), and their resultant must be zero, because the suitcase is moving with constant velocity (which means acceleration equals zero, so according to Newton's second law: F=ma, the net force is zero). So we can write:

F_x - F_f=0\\F_x = F_f\\F cos \theta = \mu mg\\F=\frac{\mu mg}{cos \theta}=\frac{(0.33)(8.2 kg)(9.8 m/s^2)}{cos(41.9^{\circ})}=35.6 N

8 0
3 years ago
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