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Artemon [7]
3 years ago
7

Sabrina's flying disc was stuck in a tree. In order to get the flying disc down, she used a 25-foot ladder positioned 8 feet fro

m the base of the tree. How high was the flying disc? Round your answer to the nearest tenth if necessary.

Mathematics
1 answer:
TEA [102]3 years ago
7 0
A^2+b^2=c^2
b^2=561
\sqrt{561}

Answer; 23.7 feet tall
Hope this helped!



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Dvinal [7]

Its ‘B’

100% sure

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4 0
3 years ago
In ΔBCD, the measure of ∠D=90°, the measure of ∠C=83°, and DB = 95 feet. Find the length of BC to the nearest tenth of a foot.
Paha777 [63]

Answer:

95.7

Step-by-step explanation:

\sin C = \frac{\text{opposite}}{\text{hypotenuse}}=\frac{95}{x}

sinC=

hypotenuse

opposite

​

=

x

95

​

\sin 83=\frac{95}{x}

sin83=

x

95

​

x\sin 83=95

xsin83=95

Cross multiply.

\frac{x\sin 83}{\sin 83}=\frac{95}{\sin 83}

sin83

xsin83

​

=

sin83

95

​

Divide each side by sin 83.

x=\frac{95}{\sin 83}=95.7134\approx 95.7\text{ feet}

x=

sin83

95

​

=95.7134≈95.7 feet

Type into calculator and roundto the nearest tenth of a foot.

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3 years ago
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Kisachek [45]

Answer:

31.06

Step-by-step explanation:

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