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Delicious77 [7]
3 years ago
6

A body on the surface of a planet with the same radius as Earths weighs 10 times more than it does on Earth. What is the mass of

this planet in terms of Earths mass?
Physics
1 answer:
nadya68 [22]3 years ago
6 0

Answer:

Explanation:

Given

radius of Planet is equal to radius of Earth

r_p=r_e

Weight of body on Planet F_p=mg_p

where m=mass of body

g_p=acceleration\ due\ to\ gravity\ on\ surface\ of\ Planet

Weight of body on earth F_e=mg_e

g_e=acceleration\ due\ to\ gravity\ on\ Earth

acceleration due to gravity is given by

g=\frac{GM}{r^2}

where G=gravitational constant

M=mass of Planet

r=radius of planet

for earth g_e=\frac{GM_e}{r_e^2}

for planet g_p=\frac{GM_p}{r_p^2}

substituting these values in F_e and F_p

F_p=m\times \frac{GM_p}{r_p^2}---1

F_e=m\times \frac{GM_e}{r_e^2}---2

divide 1 and 2

\frac{F_p}{F_e}=\frac{m\times \frac{GM_p}{r_p^2}}{m\times \frac{GM_e}{r_e^2}}

10=\frac{M_p}{M_e}

M_p=10M_e

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7 0
2 years ago
A 0.405 kg mass is attached to a spring with a force constant of 26.3 N/m and released from rest a distance of 3.31 cm from the
miv72 [106K]

Answer:

0.231 m/s

Explanation:

m = mass attached to the spring = 0.405 kg

k = spring constant of spring = 26.3 N/m

x₀ = initial position = 3.31 cm = 0.0331 m

x = final position = (0.5) x₀ = (0.5) (0.0331) = 0.01655 m

v₀ = initial speed = 0 m/s

v = final speed = ?

Using conservation of energy

Initial kinetic energy + initial spring energy = Final kinetic energy + final spring energy

(0.5) m v₀² + (0.5) k x₀² = (0.5) m v² + (0.5) k x²

m v₀² + k x₀² = m v² + k x²

(0.405) (0)² + (26.3) (0.0331)² = (0.405) v² + (26.3) (0.01655)²

v = 0.231 m/s

8 0
4 years ago
Complete each statement with the word that makes it true.
Nuetrik [128]

Answer:

reactive

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Explanation:

5 0
3 years ago
The speed of light in air is 3 x 108 m/s. The speed of light in ice is 2.29 x 108 m/s. What is the refractive index from air to
Studentka2010 [4]

Answer:

η = 1.31

Explanation:

The formula for the refractive index of from air to some other medium is given by the following formula:

\eta = \frac{c}{v}\\

where,

η = refractive index = ?

c = speed of light in air = 3 x 10⁸ m/s

v = speed of light in ice = 2.29 x 10⁸ m/s

Therefore, using these values in the equation we get:

\eta = \frac{3\ x\ 10^8\ m/s}{2.29\ x\ 10^8\ m/s} \\

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4 0
3 years ago
A transport plane takes off from a level landing field with two gliders in tow, one behind the other. The mass of each glider is
velikii [3]

Answer:

(a)  Length =136.58 m

(b)  T=5995 N

Explanation:

for the glider in the back

T - 1900 = 700 a

for the glider in front

12000-T -1900 = 700a

add equations

12000-3800 = 1400 a

a=5.85 m/s^2

v^2 = v0^2 + 2 a x

40^2 = 2*5.85*x

Length =136.58 m

b) plug the a back into one of the previous formula

T -  1900 = 700*5.85

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8 0
3 years ago
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