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solmaris [256]
2 years ago
8

Which substance is a gas at room temperature and atmospheric pressure?

Physics
1 answer:
s2008m [1.1K]2 years ago
3 0

Answer:

Explanation:

A) Hg is mercury, a metal that is mostly liquid at STP (Standard Temp and Pressure), though some small portion of it will be gaseous in a closed container.

B) CH Methylidyne radical is a gas

It is not a stable compound because carbon has four valence electrons and only one of those is kept occupied by the hydrogen atom.

If this is supposed to be CH₄ which is methane, then also a gas at STP

C) C₂H₅OH is ethanol which is mostly a liquid at STP, though some small portion of it will be gaseous in a closed container.

D) H₂O is water and will be mostly liquid at STP, though some small portion of it will be gaseous in a closed container.

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Dissolving common salt in water is physical or chemical change?
Ipatiy [6.2K]

Answer: Physical

Explanation: There are no changes being done to the salt. Think of it this way, if you dissolve the salt in water then boil the water completely, you will have the same salt you started with.

8 0
3 years ago
If you can’t open the lid of a jelly jar what should you do?
9966 [12]

If I can't open the lid of a jelly jar, I'd keep trying and if I can't open the lid of a jelly jar after the MANY tries I took, I'd ask for help.

6 0
3 years ago
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What must occur for work to be done on an object?
katrin2010 [14]
The answer is D) the object must move. The definition of work is movement (in any form).

Hope this helped! If it did, would you mind marking my answer as Brainliest? Thanks :D
8 0
3 years ago
When the Apollo 11 lunar module Eagle lands on the moon it comes to a stop 10m above the surface of the moon. The last 10m it fr
Scrat [10]

Answer:

i) 3.514 s, ii) 5.692 m/s

Explanation:

i) We can use Newton's second law of motion to find out how long does it take for the Eagle to touch down.

as the equation says for free-falling

h = ut +0.5gt^2

Here, h = 10 m, g = acceleration due to gravity = 1.62 m/s^2( on moon surface)

initial velocity u = 0

10 = 0.5×1.62t^2

t = 3.514 seconds

Therefore, it takes t = 3.514 seconds for the Eagle to touch down.

ii) use Newton's 1st equation of motion to calculate the velocity of the lunar module when it hits the surface of the moon

v = u + gt

v = 0+ 1.62×3.514

v= 5.692 m/s

7 0
3 years ago
Kid A has jumped off the sled! (RIP)
balandron [24]

Answer:

46.45 m/s

Explanation:

Total momentum before jump = Total momentum after jump

11.7 * ( 36.7 + 45.2 ) = ( 36.7 * (-31.1) ) + ( 45.2 * v )

v*45.2 - 1141.37 = 958.23

v = 2099.6/45.2 = 46.45

5 0
3 years ago
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