Distance= speed (multiplied by) time
The average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.
<h3>Acceleration of the box</h3>
The acceleration of the box is calculated as follows;
vf² = vi² + 2as
a = (vf² - vi²)/2s
a = (11.5² - 13²) / (2 x 8.5)
a = -2.16 m/s²
<h3>Time of motion of the box</h3>
The time taken for the box to travel is calculated as follows;
a = (vf - vi)/t
t = (vf - vi) / a
t = (11.5 - 13) / (-2.16)
t = 0.69 s
<h3>Average power supplied by the friction</h3>
P = Fv
P = (ma)(vf - vi)
P = (1 x -2.16) x (11.5 - 13)
P = 3.24 W
Thus, the average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.
Learn more about average power here: brainly.com/question/19415290
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Answer:
The answer is: Increase the Number of Ropes/Pulleys.
Explanation:
A "pulley" <u><em>is an object that supports a particular movement such as supporting a force's change in direction (provided that the direction is applied to a cord). </em></u>This is regarded as a "simple machine" consisting of a wheel on an axle. This helps guide cables or ropes.
This machine is used <em>in order to decrease the amount of time it takes to do work, such as lifting of objects.</em>
Remember that "mechanical advantage"<u> refers to the ratio between the force applied to a machine and the force produced by it.</u> So, when it comes to pulleys, the mechanical advantage increases when the number of ropes are also increased. They are directly proportional. This goes the same way with increasing the number of pulleys. Once you increase the number of pulleys, the mechanical advantage also increases.
Answer:
The density of the mixture is 0.55kg/m^3
Explanation:
P = 1bar = 100kN/m^2, T = 0°C = 273K, n = 0.4+0.6 = 1mole
PV = nRT
V = nRT/P = 1×8.314×273/100 = 22.70m^3
Mass of N2 = 0.4×28 = 11.2kg
Mass of H2 = 0.6×2 = 1.2kg
Mass of mixture = 11.2 + 1.2 = 12.4kg
Density of mixture = mass/volume = 12.4/22.7 = 0.55kg/m^3
(1/2)^x=1/16
ln 1/2^x=x ln 1/2=ln 1/16
x=4
4 half-lives in one hour=1/4 hour for the half-life of the isotope
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