Answer:
A mass is suspended on a spring. The spring is compressed so that the mass is located 5 cm above its rest position. The mass is released at time t = 0 and allowed to oscillate. It is observed that the mass reaches its lowest points after it is released. Find an equation that describes the motion of the mass.
1/2
Explanation:
We do not start at y=0y=0 so it is better to use a cosine curve. The hanging string is compressed to a position that is y=5y=5 units above the rest position. Hence, |a|=5∣a∣=5. Also, since we begin at positive values, then a=5a=5.
We begin at the highest point y=5y=5.
Please vote me as brainliest
Answer:
0.00119
Explanation:
F = Force = 44500 N
A = Area =
E = Young's modulus of copper =
Stress is given by
Strain is given by
The resulting strain is 0.00119
Answer:
The correct answer would be 200m
Explanation:
20x10=200
the previous answer is incorect from the other user.
Answer:
The x - intercept is 1/3
The y - intercept is 1/2
The gradient is -3/2
Explanation:
To find the x - intercept of the equation 2y + 3x = 1, we find the value of x when y = 0. So,
2y + 3x = 1
2(0) + 3x = 1
0 + 3x = 1
3x = 1
x = 1/3
So, the x - intercept is 1/3
To find the y - intercept of the equation 2y + 3x = 1, we find the value of y when x = 0. So,
2y + 3x = 1
2y + 3(0) = 1
2y + 0 = 1
2y = 1
y = 1/2
So, the y - intercept is 1/2
To find the gradient of the equation 2y + 3x = 1, we re-write it in gradient intercept form by making y subject of the formula.
So, 2y + 3x = 1
2y = -3x + 1
y = -3x/2 + 1/2
The coefficient of x which equals -3/2 is the gradient.
The gradient is -3/2