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miskamm [114]
4 years ago
7

The energy expenditure value of traveling by car is 3.6 MJ/passenger-kilometer. For one person making a trip of 1000 km, if a ga

llon of gasoline contains 120 MJ, approximately how many gallons of gasoline would be required
Physics
1 answer:
mash [69]4 years ago
8 0

Answer:

30[gal] would be requiered.

Explanation:

The consumption ratio is given by the following expression:

\frac{3.6[MJ]}{[1pass-km]}

To find the amount of energy needed we must multiply the ratio by the number of passengers, in this way the unit passenger-kilometer is removed from the denominator.

\frac{3.6[MJ]}{[1 pass-km]}*1[pass-1000km]\\\\ = 3600[MJ]

1 gal = 120 [MJ]

  x    = 3600[MJ]

x = 30 [gal]

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Warming signs before fad diet includes:

1. When a special type of diet is recommended for weight loss.

2. When quick weight loss is promised instead of advice on the need to exercise, eat healthy foods including fruits and vegetables, and adopt a good feeding behavior.

3. Promises rapid weight loss in a short period of time.

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4. Lower metabolic rates over time.

Explanation:

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A healthy weight loss plan captures the need to exercise, reduce body fats while eating healthy. Eating fruits, vegetables are also encouraged.

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What is the definition of motivation?
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A 4 kg toy car moves horizontally on a rough road with coefficient of kinetic friction 0.2. It accelerates from rest to 20 m/s i
attashe74 [19]

The total work done on the car is 784Joule.

<h3>What's the acceleration of the car?</h3>
  • As per Newton's equation of motion, V= U+at
  • U= initial velocity= 0 m/s

V= vinal velocity= 20m/s

t= time = 10s

a= acceleration

  • So, 20= 0+ 10a

=> a= 20/10= 2m/s²

<h3>What's the distance covered by the car in 10 seconds?</h3>
  • As per Newton's equation of motion,

V²-U² = 2aS

  • S= distance covered by the car
  • So, 20²-0=2×2×S=4S

=> 400= 4S

=> S= 400/4= 100m

<h3>What's the work done on the car due to frictional force?</h3>

Work done by frictional force= frictional force × distance

= (0.2×4×9.8)×100

= 784Joule

Thus, we can conclude that the work done on the car is 784Joule.

Learn more about the work done here:

brainly.com/question/25573309

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