Answer:
time to fall is 3.914 seconds
Explanation:
given data 
half distance time = 1.50 s
 
to find out
find the total time of its fall 
solution
we consider here s is total distance 
so equation of motion for distance 
s = ut + 0.5 × at²   .........1
here s is distance and u is initial speed that is 0 and a is acceleration due to gravity = 9.8 and t is time
so for last 1.5 sec distance is 0.5 of its distance so equation will be 
0.5 s = 0 + 0.5 × (9.8) × ( t - 1.5)²     ........................1
and 
velocity will be 
v = u + at 
so velocity v = 0+ 9.8(t-1.5)    ..................2
so first we find time
 0.5 × (9.8) × ( t - 1.5)² = 9.8(t-1.5)  + 0.5 ( 9.8)
solve and we get t 
t = 3.37 s
so time to fall is 3.914 seconds
 
        
             
        
        
        
Answer:
x = 5[km]
Explanation:
We must convert the time from minutes to hours.
![t=30[min]*\frac{1h}{60min}= 0.5[h]\\](https://tex.z-dn.net/?f=t%3D30%5Bmin%5D%2A%5Cfrac%7B1h%7D%7B60min%7D%3D%200.5%5Bh%5D%5C%5C)
We know that speed is defined as the relationship between space and time.

where:
x = space [m]
t = time = 0.5 [h]
v = velocity [m/s]
Now replacing:
![x = 10[\frac{km}{h} ]*0.5[h]\\x=5[km]](https://tex.z-dn.net/?f=x%20%3D%2010%5B%5Cfrac%7Bkm%7D%7Bh%7D%20%5D%2A0.5%5Bh%5D%5C%5Cx%3D5%5Bkm%5D)
 
        
             
        
        
        
<span>"A force is required to cause motion to deviate from a straight line.</span>
        
                    
             
        
        
        
Answer:
<em>W=700 Joule</em>
Explanation:
<u>Physics Work
</u>
Is the dot product of the force vector by the displacement vector

When both the force and the displacements are pointed in the same direction, the formula reduces to its scalar version

The weightlifter is applying a net force of 350 N to lift the weights a distance of 2 m, thus the net work done is

 
        
             
        
        
        
4. E
5. D
6. F
Hope this helps