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elixir [45]
3 years ago
7

Two charged objects attract each other with a certain force. If the charge on one of the objects is doubled with no change in th

e other or the separation, the force between them
A.) quadruples
B.) doubles
C.) halves
D.) increases, but we can't say how much without knowing the distance between them
Physics
1 answer:
Vanyuwa [196]3 years ago
4 0
It is B. secod try i know its dumb but im trying to cheer myself up
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Consider 2 steel rods, A and B, B has three times the area and twice the length of A, so young modulus of B will be what factor
AVprozaik [17]

Answer:

  \frac{Y}{Y_o} = 2/3

Explanation:

The yuong modulus of a rod is defined as the relationship between the tensile strength and the strain

         Y =  \frac{ \frac{F}{A} }{\frac{\Delta L}{L_o} }

let's use the subscript "o" for rod A

         I = \frac{ \frac{F}{A_o} }{ \frac{\Delta L}{L_o} }

tells us that rod B has

         A = 3 A₀

         L = 2 L₀

we substitute

         Y = \frac{ \frac{F}{A} }{ \frac{\Delta L}{L} }

          Y = \frac{ \frac{F}{3A_o} }{ \frac{\Delta L}{ 2L_o}  }

         y = ⅔  \frac{ \frac{F}{A_o}}{ \frac{\Delta }{L_o} }

substituting the value of Y₀

          Y = ⅔  Y₀

           \frac{Y}{Y_o} = 2/3

5 0
3 years ago
An object is released from rest at time t = 0 and falls through the air, which exerts a resistive force such that the accelerati
rosijanka [135]

Answer:

A) \frac{g}{b}(1-e^{-bt})

Explanation:

Since a = g - bv,

We can substitute a = dv/dt into the equation.

Then, the equation will be like dv/dt = g - bv.

So we got first order differential equation.

As known, v = 0 at t = 0, and v = g/b at t = ∞.

Since \frac{dv}{dt}= g - bv = b( \frac{g}{b} - v) ⇒ \frac{dv}{ \frac{g}{b} - v}= bdt

So take the integral of both side.

- ln (\frac{g}{b} - v) = bt + C

Since for t=0, v = 0 ⇒ C =- ln (\frac{g}{b})

v = \frac{g}{b} + e^{-bt-ln(\frac{g}{b})} = \frac{g}{b}- \frac{g}{b}e^{-bt} = \frac{g}{b}(1-e^{-bt})

5 0
3 years ago
S When an uncharged conducting sphere of radius a is placed at the origin of an x y z coordinate system that lies in an initiall
telo118 [61]

The sphere has a constant potential. It is the electric field.

E = V_{0} = 0

In the sphere, then

E_{x} = 0,  E_{y}=0,   E_{z}=0

Outside the sphere, then

V = V_{0} - E_{0}z + \frac{E_{0}a^{3}z}{(x^{2} +y^{2} + z^{2})^{3/2}   }

The elements of the electric field include

E_{x} =\frac{3E_{0}a^{3}xy}{(x^{2} +y^{2} +z^{2})^{5/2}}\\E_{y} = \frac{3E_{0}a^{3}xz}{(x^{2} +y^{2}+z^{2})^{5/2}}

Which becomes,

=E_{0} (1-\frac{a^{3}}{x^{2} +y^{2}+z^{2})^{3/2}}+\frac{3a^{3}z^{2}}{(x^{2} +y^{2}+z^{2})^{5/2}})

<h3>In a consistent electric field, is force constant?</h3>

Similar to an ordinary object in the uniform gravitational field near the Earth's surface, a charged item in a uniform electric field experiences a constant force and consequently experiences a uniform acceleration. The vector cross product of p and E determines the torque's direction.

If the charge is positive, the force either moves in the same direction as E or in the opposite direction (if charge is negative).

A torque is experienced by an electric dipole (p) in an even electric field (E). The vector cross product of p and E determines the torque's direction.

To learn more about uniform electric field, visit

brainly.com/question/17426130

#SPJ4

5 0
2 years ago
In which state of matter is there no particle motion
Vladimir79 [104]
E, there is no state of matter that has no particle motion, however a solid's particles are only vibrating.
6 0
3 years ago
What is the resultant force acting on an object? The first force is 45 N West and the second is 23 N East.
Paul [167]

Answer:

22N West

Explanation:

45-23 because they are in opposite directions.

4 0
3 years ago
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