The given dimensions of 9.5, 6, 7, and 6.5 cm gives the following
perimeter and area of the trapezium.
<h3>How can the area and perimeter of the trapezium be found?</h3>
The perimeter of a trapezoid is given as follows;
Perimeter = The sum of the lengths of the sides
Which gives;
Perimeter = 6 + 7 + 6.5 + 9.5 = 29
The perimeter of the trapezoid =<u> 29 cm</u>
The area of the trapezoid is given as follows;
Which gives;
The area of the trapezoid = 49.5 cm²
Learn more about the area and perimeter of geometric shapes here:
brainly.com/question/359059
brainly.com/question/11461461
Answer:
(3 ± √23 * i) /4
Step-by-step explanation:
To solve this, we can apply the Quadratic Equation.
In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)
Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4
Plugging these values into our equation, we get
x = (-b ± √(b²-4ac))/(2a)
x = (-(-3) ± √(3²-4(2)(4)))/(2(2))
= (3 ± √(9-32))/4
= (3 ± √(-23))/4
= (3 ± √23 * i) /4
Basically, this problem is saying that if you multiply x by 3, then you will get a number that is one less than y. So, if you switch that around a bit, then the problem is saying that if you subtract 3x from y, you'll get 1.
Your final answer should be y - 3x = 1.
If the number on the right of the number you're trying to round is greater than 5, round it up. If the number on the right of the number you're trying to round is less than 5, round down.
So you're trying to round to the nearest whole number, look on the number on the right, it's bigger than 5, it's a 7. Therefore, round the whole number up so it would be 7.
