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Levart [38]
3 years ago
11

Solve for x and y x+y=1 2y-x=8

Mathematics
1 answer:
lara31 [8.8K]3 years ago
7 0

Answer:

(- 2, 3 )

Step-by-step explanation:

Given the 2 equations

x + y = 1 → (1)

2y - x = 8 → (2)

Adding the 2 equations term by term will eliminate the x- term

(x - x) + (y + 2y) = (1 + 8), that is

3y = 9 ( divide both sides by 3 )

y = 3

Substitute y = 3 into either of the 2 equations and solve for y

Substituting y = 3 in (1)

x + 3 = 1 ( subtract 3 from both sides )

x = - 2

Solution is (- 2, 3 )

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Answer:

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Step-by-step explanation:

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the formula for finding the volume of a cylinder is πr² · h

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5 0
3 years ago
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If f(x) = x^3 – 10x^2 + 29x – 30 and f(6) = 0, then find all<br> of the zeros of f(x) algebraically.
tino4ka555 [31]
Step 1: 1

(((x3) - (2•5x2)) + 29x) - 30 = 0

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Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 29x-30
Group 2: -10x2+x3

Pull out from each group separately :

Group 1: (29x-30) • (1)
Group 2: (x-10) • (x2)

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3 years ago
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4 years ago
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You invested money in two funds. Last year, the first fund paid a dividend of 9% and the second a dividend of 3%, and you receiv
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3 years ago
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