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2 years ago

6

A trapezoid is made of a square with side lengths of 7 feet and an isosceles right triangle whose base and height are both 7 fee

t.What is the area?

1 answer:

SVETLANKA909090 [29]2 years ago

7 0

Check the picture below.

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10. Both x and y vary inversely with each other. When x is 10, y is 6,which of the following is not a possible pair of correspon

elena55 [62]

9514 1404 393

Answer:

D) 45 and 1.2

Step-by-step explanation:

The "varies inversely" relationship is described by the equation ...

y = k/x . . . . . . y varies inversely with x (and vice versa)

The value of k can be found from known values of x and y:

xy = k . . . . . . multiply the above equation by x

(10)(6) = k = 60 . . . . using the given values

__

To check if a given pair of numbers satisfies ...

y = 60/x

you can multiply them together to see if the product is 60.

(A) 12×5 = 60

(B) 15×4 = 60

(C) 25×2.4 = 60

(D) 45×1.2 = 54 . . . . . not a possible pair of corresponding values.

45 and 1.2 are not a possible solution for x and y.

8 0

2 years ago

Find a in the figure below and place the value in the empty box

AleksAgata [21]

Answer:

a = 12m

Step-by-step explanation:

In order to solve this problem we will need to know the Pythagoras theorem that states that in a right angled triangle the square of the hypotenuse (the side opposite to the right angel) is equal to the sum of the squares of the other two sides. This theorem can be written as an equation....

$c^{2} = a^{2} + b^{2}$

Now we can see that we can easily find the missing value by using this theorem. We just have to substitute the values. And we get the following

$c^{2} = a^{2} + b^{2}$

$a^{2} = c^{2} - b^{2}$

$a^{2} = 15^{2} - 9^{2}$

$a^{2} = 225 - 81$

$a^{2} = 144$

$a = \sqrt{144}$

$a = 12$

7 0

2 years ago

Traveling 1,200 miles in 4 hours

Dafna1 [17]

Answer:

speed is 240 miles per hour

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Simplify: -1 | 2/3 - 4 | / 5/6

stealth61 [152]

Answer:

<h3>4</h3>

Step-by-step explanation:

$- 1 | \frac{2}{3} - 4| \div \frac{5}{6} \\ - 1 | \frac{2}{3} - \frac{4 \times 3}{1 \times 3} | \div \frac{5}{6} \\ - 1 | \frac{2 - 12}{3} | \div \frac{5}{6} \\ - 1 | \frac{ - 10}{3} | \div \frac{5}{6} \\ \frac{10}{3} \div \frac{5}{6} \\ \frac{10}{3} \times \frac{6}{5} \\ \frac{2}{1} \times \frac{2}{1} = 4$

3 0

2 years ago

Alan found the value of the expression (15 - 6)2 to be 189. Is he right?

tatuchka [14]

Answer would be C

Because I always use the rule of :
B - Brackets
I - indices
D - division
M - multiplication
A - addition
S - subtraction

3 0

2 years ago