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olya-2409 [2.1K]
3 years ago
5

I give brainliest pls help

Chemistry
1 answer:
Finger [1]3 years ago
7 0

Answer:

c

Explanation:

because the fire gives off radiation

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What is the mass of 2.90 ×1022 formula units of NaOH (Molar mass = 40.0 g/mol)?
enyata [817]
<h3>Solution:</h3>

\text{mass of NaOH = 2.90 × 10²² NaOH formula units} × \frac{\text{1 mol NaOH}}{\text{6.022 × 10²³ NaOH formula units}} × \frac{\text{40.0 g NaOH}}{\text{1 mol NaOH}}

\boxed{\text{mass of NaOH = 1.926 g}}

5 0
3 years ago
Read 2 more answers
If an atom, such as hydrogen, is able to form a covalent bond, describe what happens when the electron shells of two atoms overl
Ratling [72]
If two shells overlap, they start to share electrons and thus, a bond is formed
7 0
3 years ago
I will give brainliest!!! What is the density of a sample of chlorine gas that exerts a pressure of 4.5 atm in a 12.6 L containe
labwork [276]

Answer : The density of a sample of chlorine gas is, 12.59 g/L

Explanation :

To calculate the density of chlorine gas we are using ideal gas equation.

PV=nRT\\\\PV=\frac{w}{M}RT\\\\P=\frac{w}{V}\frac{RT}{M}\\\\P=\frac{\rho RT}{M}

where,

P = pressure of chlorine gas = 4.5 atm

V = volume of chlorine gas = 12.6 L

n = number of moles of chlorine gas

w = mass of chlorine gas

R = gas constant = 0.0821 L.atm/mol.K

T = temperature of chlorine gas = 36^oC=273+36=309K

M = molar mass of chlorine gas = 71 g/mol

Now put all the given values in the above formula, we get:

P=\frac{\rho RT}{M}

4.5atm=\frac{\rho \times (0.0821L.atm/mol.K)\times (309K)}{71g/mol}

\rho=12.59g/L

Therefore, the density of a sample of chlorine gas is, 12.59 g/L

7 0
3 years ago
A piece of metal with a mass of 23.2 g at 120.1oC is placed in a styrofoam cup containing 35.0 g of water at 22.2oC. Once the sy
earnstyle [38]

Answer:

0.8797 J/g oC

Explanation:

use mcAT=mcaT

3 0
2 years ago
What is the molarity of a hydrochloric acid solution, when 30.0 mL is neutralized by 48.0 mL of 0.100 mol/L
bulgar [2K]

The molarity of a hydrochloric acid solution : 0.32 M

<h3>Further explanation  </h3>

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution).

Titrations can be distinguished including acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases is used.  

Acid-base titration formula  

Ma. Va. na = Mb. Vb. nb  

Ma, Mb = acid base concentration  

Va, Vb = acid base volume  

na, nb = acid base valence  

1 ⇒HCl (valence=1, HCl ⇒H⁺+Cl⁻, one H⁺)

2⇒Ca(OH)₂(valence=2, Ca(OH)₂⇒Ca²⁺+2OH⁻, two OH⁻)

M₂=0.1 M

V₂=48 ml=0.048 L

V₁=30 ml=0.03 L

\tt M_1.V_1.n_1=M_2.V_2.n_2\\\\M_1\times 0.03\times 1=0.1\times 0.048\times 2\\\\M_1=0.32

3 0
3 years ago
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