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Sergio [31]
1 year ago
9

12.53 (syn) show how each of these compounds can be produced from an alkene or alkyne. draw the appropriate alkene or alkyne and

include any necessary reagents and special reaction conditions.
Chemistry
1 answer:
sveta [45]1 year ago
3 0

The structures of alkanes and alkynes are given below in the diagram.

In organic chemistry, when an organic compound contains atoms joined only by single covalent bonds, the compound is said to be saturated and this saturated hydrocarbons are known as alkanes. For example propane  that is shown in the diagram attached below. When an organic compound contains carbon atoms joined by double(alkene) or triple(alkyne) covalent bonds, the compound is said to be unsaturated. For example propene and propyne as shown in the diagram.

Furthermore, the hydrocarbons that possess a set of carbon-carbon double covalent bonds,>C=C<, in their carbon chains form the homologous series called alkenes while those possessing a set of carbon-carbon triple covalent bond in their carbon chains form the alkyne series.

Learn more about alkanes and alkynes from the link given below.

brainly.com/question/6818114

#SPJ4

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The number of oxygen atoms in 48.0g of oxygen gas
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Answer:

Now u have 48 g of O2. There. Fore mole=weight/M. W. Of oxygen. Therefor 3mole.

After that if we to multiply the avogadro number with it. So 3 *NA

Now u want only atom calculation then we have 2 molecule of oxygen then multiply it with 2 too.

So final claculation is =3*2*NA.

Explanation:

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Kryger [21]

The empirical formula : C₁₂H₄F₇

The molecular formula : C₂₄H₈F₁₄

<h3>Further explanation</h3>

mol C (MW=12 g/mol)

\tt \dfrac{18.24}{12}=1.52

mol H(MW=1 g/mol) :

\tt \dfrac{0.51}{1}=0.51

mol F(MW=19 g/mol)

\tt \dfrac{16.91}{19}=0.89

mol ratio of C : H : O =1.52 : 0.51 : 0.89=3 : 1 : 1.75=12 : 4 : 7

Empirical formula : C₁₂H₄F₇

(Empirical formula)n=molecular formula

( C₁₂H₄F₇)n=562 g/mol

(12.12+4.1+7.19)n=562

(281)n=562⇒ n =2

Molecular formula : C₂₄H₈F₁₄

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