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Sindrei [870]
3 years ago
13

15+9=? (5+3) What number is missing from the expression?

Mathematics
1 answer:
Airida [17]3 years ago
4 0

Answer:

<h3>\boxed{ \boxed{ \bold{  \mathsf{3}}}}</h3>

Step-by-step explanation:

Let the missing number be 'x'

⇒\mathsf{15 + 9 = x(5 + 3)}

Distribute x through the parentheses

⇒\mathsf{15 + 9 = 5x + 3x}

Swap the sides of the equation

⇒\mathsf{5x + 3x = 15 + 9}

Add the numbers

⇒\mathsf{5x + 3x = 24}

Collect like terms

⇒\mathsf{8x = 24}

Divide both sides of the equation by 8

⇒\mathsf{ \frac{8x}{8}  =  \frac{24}{8} }

Calculate

⇒\mathsf{x = 3}

Hope I helped!

Best regards!

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Answer:

\frac{2708}{333}

Step-by-step explanation:

0.132132132...=\frac{132}{999}=\frac{44}{333} \\\\8+0.132132132=8+\frac{44}{333}\\\\=\frac{8(333)}{333}+\frac{44}{333}\\\\=\frac{2664}{333}+\frac{44}{333}\\\\=\frac{2708}{333}

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Which expression is equivalent in to the given expression? Assume the denominator does not equal zero.
marusya05 [52]

The equivalent expression of 14r^4y^6/7r^8y^2 is 2y^4/r^4

<h3>How to determine the equivalent function?</h3>

The expression is given as:

14r^4y^6/7r^8y^2

Start by dividing 14 by 7

2r^4y^6/r^8y^2

Next divide y^6 by y^2

2r^4y^4/r^8

Lastly divide r^4 by r^8

2y^4/r^4

Hence, the equivalent expression of 14r^4y^6/7r^8y^2 is 2y^4/r^4

Read more about equivalent expression at:

brainly.com/question/2972832

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2 years ago
Solve for x and y 1/(x+yi) + 2/(x-yi) = 1+i
aliina [53]

Answer:

Step-by-step explanation:

x+i*y≠0 ==> x≠0 and y≠0

x-i*y≠0 ==> x≠0 and y≠0

We must exclude (0,0) as solution.

\dfrac{1}{x+i*y} +\dfrac{2}{x-i*y} =1+i\\\\\dfrac{1*(x-i*y)}{(x+i*y)(x-i*y)} +\dfrac{2*(x+i*y)}{(x-i*y)(x+i*y)} =1+i\\\\\\\dfrac{x-i*y+2x+2i*y}{x^2+y^2} =1+i\\\\3x+i*y=(1+i)(x^2+y^2)\\\\3x+i*y=(x^2+y^2)+i(x^2+y^2+i*(x^2+y^2)\\\\\left\{\begin{array}{ccc}3x&=&x^2+y^2\\y&=&x^2+y^2\\\end {array}\right.\\\\\\\left\{\begin{array}{ccc}y&=&3x\\3x&=&x^2+9x^2\\\end {array}\right.\\\\\\\left\{\begin{array}{ccc}y&=&3x\\x(10x-3)&=&0\\\end {array}\right.\\\\

\left\{\begin{array}{ccc}x&=&0\\y&=&0\\\end {array}\right.\ (to\ exclude) \ or \ \left\{\begin{array}{ccc}x&=&\dfrac{3}{10}\\\\y&=&\dfrac{9}{10}\\\end {array}\right.\\\\Sol=\{(\dfrac{3}{10},\dfrac{9}{10})\}\\

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