H2SO4 or hydrogen sulfate is an acid and NaOH or sodium hydroxide is a base or an alkali. The reaction between an acid and a base or alkali produces a salt and water. The reaction between these substances is shown below:
H2SO4 (aq) + 2NaOH (aq)------>2H20 (L) + Na2SO4 (aq). The salt produced in this reaction is sodium sulfate.
Mixed economy. Wherever the private and public sector have an active role, they are determined to be a mixed economy.
1) Start by standardizing the solution of NaOH by using the solution of H2SO4 whose concentration is known.
2) Equation:
2Na OH + H2SO4 --> Na2 SO4 + 2H2O
3) molar ratios
2 mol NaOH : 1 mol H2SO4
4) Number of moles of H2SO4 in 50.0 ml of 0.0782 M solution
M = n / V => n = M*V = 0.0782 M * 0.050 l = 0.00391 mol H2SO4
5) Number of moles of NaOH
2 moles NaOH / 1mol H2SO4 * 0.00391 mol H2SO4 = 0.00782 mol NaOH
6) Concentration of the solution of NaOH
M = n / V = 0.00782 mol / 0.0184 ml = 0.425 M
7) Standardize the solution of HCl
Chemical reaction:
NaOH + HCl --> NaCl + H2O
8) Molar ratios
1 mol NaOH : 1 mol HCl
9) Number of moles of NaOH in 27.5 ml
M = n / V => n = M * V = 0.425 M * 0.0275 l = 0.01169 moles NaOH
10) Number of moles of HCl
1 mol HCl / 1mol NaOH * 0.01169 mol NaOH = 0.01169 mol HCl
11) Concentration of the solution of HCl
M = n / V = 0.01169 mol / 0.100 l = 0.1169 M
Rounded to 3 significant figures = 0.117 M
Answers:
[NaOH] = 0.425 M
[HCl] = 0.117 M
Answer: The correct option is:

Explanation:
In balanced chemical equation , mass of the reactants is always equal to the mass of the products.

This is the balanced equation because on both sides number of sodium and bromine atoms are same.
On the reactant side there are two sodium atoms and two bromine atoms
On the product side there are also two sodium atoms and two bromine atoms in NaBr.
Mass of reactants (here 2Na and
)= Mass of products(here 2NaBr)
2(23u) + 2(79.9u) = 2(23u + 79.9u) = 205 u
Answer: 613Hm2 x tan (x101 10
3)
Explanation:
- convert the decimal to a fraction
- calculate the product
- transform the expression
- simplify the radical expression
- okay i recommend photomath because idek this work i got these answers from the app so yeah good luck