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BaLLatris [955]
3 years ago
15

Avogadro named the quantity of the mole after himself? True or False explain??

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
3 0

Answer:

False

Explanation:

The term was first "officially" used by French physicist Jean Baptiste Perrin. He technically referenced the works of Avogadro

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Why is xenon monatomic but bromine is diatomic
WARRIOR [948]
B 3-4 is the auto
If it’s needs
8 0
2 years ago
A sample contains 16. 75 g of the radioisotope U-236 and 50. 25 g of its daughter isotope, Th-232. How long did it take for deca
garri49 [273]

The time taken for the isotope to decay is 46 million years.

We'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:

  • Original amount (N₀) = 50.25 g
  • Amount remaining (N) = 16.75
  • Number of half-lives (n) =?

2ⁿ = N₀ / N

2ⁿ = N₀ / N

2ⁿ = 50.25 / 16.75

2ⁿ = 3

Take the log of both side

Log 2ⁿ = 3

nLog 2 = Log 3

Divide both side by log 2

n = Log 3 / Log 2

n = 2

Finally, we shall determine the time.

  • Half-life (t½) = 23 million years
  • Number of half-lives (n) = 2
  • Time (t) =?

t = n × t½

t = 2  × 23

t = 46 million years

Learn more about half-life: brainly.com/question/25927447

8 0
2 years ago
Read 2 more answers
If 16 moles of al react with 3 moles of S8 how many moles of Al2 S3 will be formed
Gnom [1K]

Answer:

8 moles

Explanation:

Al reacts with S_8 to produce Al_2S_3 as

Al+S_8\rightarrow Al_2S_3

The balanced chemical equation is

16Al+3S_8\rightarrow 8Al_2S_3

In the reaction, 16 moles of Al react with 3 moles of S_8 to produce 8 moles of Al_2S_3.

8 0
2 years ago
Suppose a 10.0 mL sample of an unknown
mote1985 [20]

The concentration of HCl is equal to 2.54mol/L.

<h3>Mole calculation</h3>

To solve this question, one must use the molarity calculation, which corresponds to the following expression:

                                               M = \frac{mol}{v}

Thus, to find the molarity of the sample, the following calculations must be performed:

V_f = 10ml + 625ml = > 635ml

                                              \frac{0.004mol}{xmol} =\frac{1000ml}{635ml}

                                                 x = 0.00254 mol

So, 0.00254 moles were added per 10ml, so we can do:

                                              \frac{0.00254mol}{xmol}= \frac{10ml}{1000ml}  \\x = 2.54mol/L

So, the concentration of HCl is equal to 2.54mol/L.

Learn more about mole calculation in: brainly.com/question/2845237

6 0
2 years ago
How many milliliters of 3.0M phosphoric acid can be made from 95mL of 5.0M solution?
zloy xaker [14]
Thats a tuff one ummmmmm 4.5 m

4 0
3 years ago
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