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mafiozo [28]
2 years ago
12

Calculate the mass of 4.95 x 10^15 Ag atoms

Chemistry
1 answer:
solmaris [256]2 years ago
4 0

Answer:

              8.87 × 10⁻⁷ grams

Explanation:

Moles = No. of Particles / 6.022 × 10²³ Particles/mol

Moles = 4.95 × 10¹⁵ atoms / 6.022 × 10²³ atoms/mol

Moles = 8.22 × 10⁻⁹ mol

Also,

Mass = Moles × M.Mass

Mass = 8.22 × 10⁻⁹ mol × 107.87 g/mol

Mass = 8.87 × 10⁻⁷ grams

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svet-max [94.6K]
Alpha I believe not sure
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Chlorine can bond with fluorine to form CIF. Chlorine can also bond with lithium to form LiCI Which compound will have a greater
Sergio [31]

Answer: ClF will have a greater partial charge.

Explanation:

A polar covalent bond is defined as the bond which is formed when there is a low difference of electronegativities between the atoms, thus resulting in charge difference. Example: ClF

Non-polar covalent bond is defined as the bond which is formed when there is no difference of electronegativities between the atoms and thus there is no charge difference. Example: F_2

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Thus as ClF will have greater partial charge.

5 0
3 years ago
The half-life of sr-90 is 28 years. after 56 years of decay only 0. 40 g of a sample remains. what was the mass of the original
Svetradugi [14.3K]

Half-life is the time taken for the concentration of the substance to reduce by 50%. The original sample of strontium had a mass of 1.6 gms. Thus, option d is correct.

<h3>What is half-life?</h3>

The half-life of any radioactive substance is the time period at which the concentration will get reduced to half the initial amount. The initial mass of Sr-90 is calculated as,

N(t) = N_{0} (\dfrac{1}{2})^{ \frac{t }{t 1/2}}

Given,

Quantity of the remaining substance N (t) = 0.40 gm

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Substituting values above:

\begin{aligned} 0.40 &= N_{0} (\dfrac{1}{2}) ^{{\frac{56}{28}}\\\\0.40 &= N_{0} (\dfrac{1}{2})^{2}\end{aligned}

= 1.6 gm

Therefore, option d. the initial mass of Sr is 1.6 gm.

Learn more about half-life here:

brainly.com/question/16145921

#SPJ4

7 0
1 year ago
A swimming pool is 5.0 m long, 4.0 m wide and 3.0 m deep. Compute the force exerted by the water against
Alona [7]
For the answer to the question above, <span>ater weights 1000kg per meter cubed. the volume of the pool is part A is 5*4*3 = 60 meters cubed </span>
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<span>part B: </span>
<span>volume: 4*4*3 = 48 meters cubed </span>
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I hope this helps.</span>
6 0
3 years ago
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