Answer:
Explanation:
Potential at a point near a charge = Q / 4πε₀ R
where Q is charge given , R is distance of point from the charge .
Q / 4πε₀ R = 40
Electric field E at A = -dV / dR
= .16 x 10⁻³ / 2 x 10⁻⁶
= .08 x 10³
= 80 N/C
E = Q / 4πε₀ R²
80 = Q / 4πε₀ R x R
80 = 40 / R
R = 40 / 80
= .5 m .
Answer:
Yes because of the temputer
Explanation:
Answer:
Although the wave slows down, its frequency remains the same, due to the fact that its wavelength is shorter. When waves travel from one medium to another the frequency never changes.
