The quantity work has to do with a force causing a displacement. Work has nothing to do with the amount of time that this force acts to cause the displacement. Sometimes, the work is done very quickly and other times the work is done rather slowly. For example, a rock climber takes an abnormally long time to elevate her body up a few meters along the side of a cliff. On the other hand, a trail hiker (who selects the easier path up the mountain) might elevate her body a few meters in a short amount of time. The two people might do the same amount of work, yet the hiker does the work in considerably less time than the rock climber. The quantity that has to do with the rate at which a certain amount of work is done is known as the power. The hiker has a greater power rating than the rock climber.
Power is the rate at which work is done. It is the work/time ratio. Mathematically, it is computed using the following equation.
Power = Work / time
or
P = W / t
According to Stefan-Boltzmann Law, the thermal energy radiated by a radiator per second per unit area is proportional to the fourth power of the absolute temperature. It is given by;
P/A = σ T⁴ j/m²s
Where; P is the power, A is the area in square Meters, T is temperature in kelvin and σ is the Stefan-Boltzmann constant, ( 5.67 × 10^-8 watt/m²K⁴)
Therefore;
Power/square meter = (5.67 × 10^-8) × (3000)⁴
= 4.59 × 10^6 Watts/square meter
Answer:
Part 1
Part 2
Explanation:
Given that
Diameter,d=1 μm
Length ,l=2 μm
As we know that volume of cylinder given as
Surface area,A
A=π d l
Part 1
Part 2
Answer:
Explanation:
Let s be displacement from equilibrium position . Restoring force
m d²s / dt² = - k s
d²s / dt² = - k /m s
Put k /m = ω
d²s / dt² + ω² s = 0
The solution of this differential equation
= s = A cosωt
Now when t = 0 , s = 2 cm
A = 2 cm
Putting the values we have
2 = A cos 0
A = 2 cm
s ( t) = 2 cos ωt
