The overall energy change that occurs when a solution forms is called the heat of solution

A race car has a mass of 710 kg. It starts from rest and travels 40 m in 3.0 s. The car is uniformly accelerated during the enti

Archy [21]

The net force applied to it is 6311.9 N.

To calculate the net force to the car, first, we need to find the acceleration using the equation of motion.

Force: This as be defined as the product of mass and acceleration of a body. The S.I unit of force is Newton (N)

⇒ Formula

S = ut+at²/2................. Equation 1

⇒ Where:

u = Initial velocity
S = Distance
t = Time
a = acceleration

From the question,

⇒Given:

S = 40 m
t = 3.0 s
u = 0 m/s (at rest)

⇒ Substitute these values into equation 1

40 = 0(3)+a(3²)/2

⇒ Solve for a

9a = 80
a = 80/9
a = 8.89 m/s²

⇒ To get the force, we use the formula below

F = ma .................... Equation 2

⇒ Where:

F = Force applied
m = mass of the car

⇒ Given:

m = 710 kg
a = 8.89 m/s²

⇒ Substitute these values into equation 2

F = 710(8.89)

F = 6311.9 N

Hence the net force applied to it is 6311.9 N.

Learn more about force here: brainly.com/question/13370981

6 0

2 years ago

A 4 kg textbook sits on a desk. It is pushed horizontally with a 50 N applied force against a 15 N frictional force.

ikadub [295]

Answer:

b) No acceleration in the vertical

c) 35N

d) 35N

e) $8.75\ m/sec^2$

Explanation:

a) The situation can be shown in the free body diagram shown in the figure below where F is the applied force, Fr is the friction force, W is the weight of the book and N is the normal force exerted vertically up from the desk to the book

b) The vertical movement is restrained by the normal force which opposes to the weight. In absence of any other force, they both are in equilibrium and the net force is zero

c) The net horizontal force acting on the book is the vectorial sum of the applied force and the friction force. Since they lie in the same axis and are opposed to each other:

$Fh_{net}=F-F_r=50 N - 15N=35N$

d) The net force acting on the book is the vector sum of all forces in all axes. The normal and the weight cancel each other in the y-axis, so our resulting force is the x-axis net force, computed as above:

$F_n=35N$ in the x-axis

e) Following Newton's second law, the acceleration is calculated as

$a=\frac{F_t}{m}=\frac{35N}{4Kg}=8.75m/sec^2$

8 0

3 years ago

The earth is made mostly of metals and rocks. Where did this material come from? It was made by nuclear fission of uranium and o

Olegator [25]

This is very very cool!

5 0

3 years ago

What is the relationship between lightning and thunder

PtichkaEL [24]

Whenever lightning strikes it separates the air where it goes. This air then rushes back together making a loud noise when it connects, creating thunder.

6 0

4 years ago

Z. A force that gives a 8-kg objet an acceleration of 1.6 m/s^2 would give a 2-kg object an

Paladinen [302]

Answer:

$\boxed {\boxed {\sf D.\ 6.4\ m/s^2}}$

Explanation:

We need to find the acceleration of the 2 kilogram object. Let's complete this in 2 steps.

<h3>1. Force of 1st Object </h3>

First, we can find the force of the first, 8 kilogram object.

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

$F=m \times a$

The mass of the object is 8 kilograms and the acceleration is 1.6 meters per square second.

m= 8 kg
a= 1.6 m/s²

Substitute these values into the formula.

$F= 8 \ kg * 1.6 \ m/s^2$

Multiply.

$F= 12.8 \ kg*m/s^2$

<h3>2. Acceleration of the 2nd Object </h3>

Now, use the force we just calculated to complete the second part of the problem. We use the same formula:

$F= m \times a$

This time, we know the force is 12.8 kilograms meters per square second and the mass is 2 kilograms.

F= 12.8 kg *m/s²
m= 2 kg

Substitute the values into the formula.

$12.8 \ kg*m/s^2= 2 \ kg *a$

Since we are solving for the acceleration, we must isolate the variable (a). It is being multiplied by 2 kg. The inverse of multiplication is division. Divide both sides of the equation by 2 kg.

$\frac {12.8 \ kg*m/s^2}{2 \ kg}= \frac{2\ kg* a}{2 \ kg}$

$\frac {12.8 \ kg*m/s^2}{2 \ kg}=a$

The units of kilograms cancel.

$\frac {12.8}{2}\ m/s^2=a$

$6.4 \ m/s^2=a$

The acceleration is 6.4 meters per square second.

4 0

3 years ago