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jonny [76]
3 years ago
8

6 • 14 - (9 + 8) 2 =

Mathematics
2 answers:
ahrayia [7]3 years ago
7 0

Use pemdas

Parenthesis

Exponents

Multiplication

Division

Addition

Subtraction

Do parenthesis first: (9+8)=17

6x14-17x2

Then do multiplication

6x14=84 17x2=34

Now do subtraction

84-34=50

Therefore your answer is 50

Nataly [62]3 years ago
4 0

Answer:

50

Step-by-step explanation:

For this question you would follow the BIDMAS rule - (Brackets, Indices, Division, Multiplication, Addition, Subtraction.)

The first thing in this question you need to solve it (9 + 8)

we do this because, when we follow BIDMAS, the first rule is brackets

so, 9 + 8 = 17

The second step is to multiply, as this rule is second,

so, 17 x 2 = 34

Our final step is to solve the last bit, which is 6 x 14

and we know that 6 x 14 = 84

So now that we have 84 and 34, we need to subtract the two numbers as shown,

84 - 34 = 50

And this is how you get the answer 50

i hope this has helped you, please comment if you did not understand it and i will explain it in another way : )

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Read 2 more answers
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Masja [62]

Answer:

n = -3

Step-by-step explanation:

2 - 2n = 3n + 17

-2                -2

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3 years ago
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3 years ago
Rephrase in contrapositive form:
miv72 [106K]

Step-by-step explanation:

Consider the provided information.

For the condition statement p \rightarrow q or equivalent "If p then q"

The rule for Contrapositive is: Negative both statements and interchange them. \sim q \rightarrow \sim p

Part (A) If you are taller than 6 ft, then it is unpleasant for you to travel in economy class.

Here p is "you are taller than 6 ft, and q is "it is unpleasant for you to travel in economy class".

It is given that Your contrapositive must not contain explicit references to negation. Assume that the negation of "unpleasant" is "pleasant".

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Part (B) "If x ≥ 0 and y ≥ 0 then xy ≥ 0" where x, y are real numbers.

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The negative of xy≥ 0 is xy<0, x ≥ 0 is x<0 and y ≥ 0 is y<0.

Remember negative means opposite.

Contrapositive: If xy < 0 then x<0 and y<0.

8 0
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