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Lilit [14]
3 years ago
6

Greg and Andrea are trying to find out how long it takes amylase, a digestive enzyme found in saliva, to break down a sample of

starch. They put their sample in a beaker and covered it with their own saliva. After allowing it to sit on the lab table for 1 hour they measured the remaining surface area of the starch. What is the best way they could improve their experiment?
Biology
2 answers:
enyata [817]3 years ago
8 0
The answer is: the amount of the saliva samples must stay consistent while the amount of starch must vary.

The amount of the saliva samples must stay consistent because amylase, present in the saliva, is the independent variable which affects the dependent variable - the amount of starch. So, amylase will do its job while remaining surface area of the starch will depend on the starting amount of the starch.
Umnica [9.8K]3 years ago
8 0

The relationship between a dependent variable and independent variable in a scientific investigation is that the dependent variable depends on the independent variable. You can also put it this way: The results depend on the factor of the experiment that differs from the controlled group.


This is why the best way they could improve their experiment is by taking consistent amounts of their saliva samples with varying amounts of starch.

I hope it helps, Regards.

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Biogeography is the study of the distribution of species in different regions through the history of life on Earth. The map belo
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<u>Answer</u>: A) Africa and South America only

As shown in the map, the fossil evidence suggests that Cynognathus lived on the modern day continents of South America and Africa. Thus, from this distribution and the fragmentation of the ancient landmass into today's continents, result in the distribution of Cynognathus offspring species also only within the continents of Africa and South America.

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Individuals with androgen insensitivity syndrome also have chromosomally abnormalities.
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This condition is caused by a genetic defect found in the X chromosome, and therefore, you can conclude your answer from this info.
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A recessive allele on the X chromosome is responsible for red-green color blindness in humans. A woman with normal vision whose
Igoryamba

Answer:

In a cross of a homozygous prevailing (AA) individual and a homozygous recessive(AA) person,  

a. on the off chance that they have a kid, what is the likelihood that the kid will be heterozygous?  

If you cross somebody who is homozygous predominant with one who is homozygous latent, the entirety of the posterity will be heterozygous (AA). Accordingly, there is a 100% possibility of delivering a posterity that is heterozygous.  

b. what is the likelihood that the youngster will be homozygous latent?  

There is no way of creating a kid that is homozygous passive. The entirety of the posterity will be heterozygous. In this way, the likelihood is zero.  

c. in the event that they have two kids, what is the likelihood of the first being homozygous prevailing and the second being homozygous passive?  

Again, this can't be determined, on the grounds that there is zero chance of delivering a posterity that is homozygous prevailing or homozygous passive. The likelihood is zero. In any case, for no reason in particular, suppose that the punnet square uncovered that there was 1/4 possibility of creating a kid that is homozygous passive. To decide the likelihood that the subsequent youngster will likewise be homozygous passive, you complete this straightforward duplication:  

1/4 x 1/4 = 1/16  

In this manner, there would be a 1/16 possibility of the subsequent kid being homozygous passive. In the event that you needed to discover the likelihood of the third kid being homozygous passive, you would do the accompanying:  

1/4 x 1/4 x 1/4 = 1/64  

Thus, there would be a 1/64 possibility of the third kid being homozygous latent. Once more, I was simply giving in model, yet it doesn't have any significant bearing right now, the entirety of the posterity will be heterozygous.  

Another question...A latent allele on the X chromosome is answerable for red-green visual weakness in people. A typical lady whose father is visually challenged weds a partially blind man. What is the likelihood that this couples child will be visually challenged?  

XX = female  

XY = male  

Let C = typical vision (predominant)  

Let c = red-green visual weakness (latent)  

A typical lady what father's identity is' partially blind must be a transporter, or heterozygous. This implies she acquired the ordinary allele from her mom and the visually challenged allele from her dad.  

Genotypes:  

Ordinary lady - Xc  

Partially blind man - Xc Y  

On the off chance that these two mate, here are the accompanying prospects:  

half of the female posterity will be bearers with ordinary vision (Xc)  

half of the female posterity will be homozygous passive and partially blind (Xc)  

half of the male posterity will have typical vision (XC Y)  

half of the male posterity will be visually challenged (Xc Y)  

In this manner, the likelihood that the couple's child will be partially blind is half, or 1/2.  

Remark  

Sheryl's Avatar  

Sheryl addressed this Was this answer accommodating?  

XX= lady, XY=man  

Alleles:  

XC=normal; Xc=colorblind  

Typical Genotypes:  

XC (typical lady)  

Xc (typical lady, yet bearer)  

Xc (visually challenged lady)  

XC Y (typical man)  

Xc Y (visually challenged man)  

Lady has typical vision, yet her dad is visually challenged. In this way, she needed to get XC from her mother (must have one, she's ordinary) and Xc from her father (it was everything he could give her): Xc  

Man is visually challenged: Xc Y  

Xc Y  

XC Y  

Xc Y

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An ester derived from glycerol and three fatty acids is a triglyceride. These are the main component of body fat in the vertebrates as well as the vegetable fat.

A Glyceride consisting of 2 fatty acid chains bonded to a glycerol molecule covalently through ester linkages is a diglyceride.

Biologically active organic compounds with four rings arranged in a specific molecular configuration are steroids.

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