By the confront theorem we know that the limit only exists if both lateral limits are equal
In this case they aren't so we don't have limit for x approaching 2, but we can find their laterals.
Approaching 2 by the left we have it on the 5 line so this limit is 5
Approaching 2 by the right we have it on the -3 line so this limit is -3
Think: it's approaching x = 2 BUT IT'S NOT 2, and we only have a different value for x = 2 which is 1, but when it's approach by the left we have the values in the 5 line and by the right in the -3 line.
Hello ,
-1/3 x + 15/3 = -4
-1/3 x + 5 = -4
-1/3 x = -4-5
-1/3 x = -9
x = -9 : -1/3
x = -9 * -3/1
x = 27 .
The Angle-Side Relationships theorem (or triangle parts relationship theorem) states that<span> if one side of a triangle is longer than another side, then the angle opposite the
longer side will have a greater degree measure than the angle opposite the shorter
side.
The converse to the </span>Angle-Side Relationships theorem (or triangle parts relationship theorem) states that if one angle of a triangle has a greater degree measure than
another angle, then the side opposite the greater angle will be longer than the
side opposite the smaller angle.
Thus, from the proof if AB > AC, then m∠C > m∠B by the <span>converse of the triangle parts relationship theorem</span>.
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