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steposvetlana [31]
4 years ago
7

A=3.14r^2 and d=12 A=?

Mathematics
1 answer:
zvonat [6]4 years ago
4 0

\huge\boxed{113.04}

Diameter (d) is equal to twice the radius (r). So, find the radius by dividing \frac{12}{2}. The radius, or r, is 6.

Substitute in the value. A=3.14*6^2

Follow the order of operations and solve the exponent first. A=3.14*36

Multiply. A=\boxed{113.04}

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Lan scores 44out of 60 maths test.what is his score as a percentage to 1 decimal place
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Step-by-step explanation:

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Which card has the solution x = 23?
morpeh [17]

I need a photo but ill give you some information this will be with exponents.

<em>Write down the problem. Here it is:</em>

<em>2^2(x+3) + 9 - 5 = 32</em>

<em>Resolve the exponent. Remember the order of operations: PEMDAS, which stands for Parentheses, Exponents, Multiplication/Division, and Addition/Subtraction. You can't resolve the parentheses first because x is in the parentheses, so you should start with the exponent, </em><em>2^2.2^2 = 4</em>

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<em>Do the multiplication. Just distribute the</em><em> 4 into (x +3)</em><em>. Here's how:</em>

<em>4x + 12 + 9 - 5 = 32</em>

<em>Do the addition and subtraction. Just add or subtract the remaining numbers. Here's how:</em>

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<em>4x+16 = 32</em>

<em>4x + 16 - 16 = 32 - 16</em>

<em>4x = 16</em>

<em>Isolate the variable. To do this, just divide both sides of the equation by 4 to find x. </em><em>4x/4 = x </em><em>and </em><em>16/4 = 4</em><em>, so </em><em>x = 4.</em>

<em>4x/4 = 16/4</em>

<em>x = 4</em>

<em>Check your work. Just plug </em><em>x = 4</em><em> back into the original equation to make sure that it checks out. Here's how:</em>

<em>2^2(x+3)+ 9 - 5 = 32</em>

<em>2^2(4+3)+ 9 - 5 = 32</em>

<em>2^2(7) + 9 - 5 = 32</em>

<em>4(7) + 9 - 5 = 32</em>

<em>28 + 9 - 5 = 32</em>

<em>37 - 5 = 32</em>

<em>32 = 32</em>

<em><u>Credit to wikiHow.com</u></em>

7 0
3 years ago
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