I need help please and thank you
2 answers:
You might be interested in
Answer:
See Below.
Step-by-step explanation:
In the given figure, AP = BP = PC.
And we want to prove that ∠ABC is a right angle.
Since AP = BP and BP = PC, we can create two isosceles triangles: ΔAPB and ΔCPB.
By the definition of isosceles triangles, in ΔAPB, ∠PAB and ∠PBA are equivalent. Let the measure of each of them be <em>x°</em>.
Likewise, in ΔCPB, ∠PCB and ∠PBC are equivalent.
And since AP = BP = PC, each of the angles∠PCB and ∠PBC will also be equivalent to <em>x°.</em>
<em />
And since the sum of the interior angles of a triangle total 180°, we acquire:
Since they are all equivalent:
Hence:
∠ABC is the sum of ∠PBA and ∠PBC, each of which measures 45°. Hence:
Answer:
y = -4x + 2
Step-by-step explanation:
y = mx + b ( slope-intercept)
1. Find Slope:
Lets name 2 as y2 and 10 as y1. And 0 as x2 and 2 as x1.
=
= -4
m/slope = -4
2. Find y-intercept:
2 = -4(0) + b
= 2 = b
Y-intercept/b = 2
3. Put into slope-intercept form:
y = mx + b
= y = -4x + 2
Hope that helps! :D