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zhuklara [117]
3 years ago
12

Place the following compounds in order of decreasing strength of intermolecular forces. I. CH3CH2CH2CH2CH2CH3 II. (CH3)3CCH3 III

. (CH3)3CCH2CH3 Group of answer choices
Chemistry
1 answer:
Vitek1552 [10]3 years ago
7 0

Explanation:

Strength of intermolecular forces depends on the number of carbon atoms present in a compound. More is the number of carbon atoms attached linearly  to each other more will be the surface area occupied by it. Hence, more is the strength of the compound.

This means that more is the branching present in a compound or lesser is the number of carbon atoms present in it then less will be the strength of intermolecular forces in the compound.

Thus, we can conclude that given compounds are placed in order of decreasing strength of intermolecular forces as follows.

CH_3CH_2CH_2CH_2CH_2CH_3 > (CH_3)_3CCH_2CH_3 > (CH_3)_3CCH_3      

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Answer:

290.82g

Explanation:

The equation for the reaction is given below:

2Al + 3H2SO4 -> Al2(SO4)3 + 3H2 now, let us obtain the masses of H2SO4 and Al2(SO4)3 from the balanced equation. This is illustrated below:

Molar Mass of H2SO4 = (2x1) + 32 + (16x4) = 2 + 32 +64 = 98g/mol

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Molar Mass of Al2(SO4)3 = (2x27) + 3[32 + (16x4)]

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From the equation above:

294g of H2SO4 produced 342g of Al2(SO4)3.

Therefore, 250g of H2SO4 will produce = (250 x 342)/294 = 290.82g of Al(SO4)3

Therefore, 290.82g of aluminium sulphate (Al(SO4)3) is formed.

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