Consider the length of diagonal is 8.5 cm instead of 8.5 m because length of perpendiculars are in cm.
Given:
Length of the diagonal of a quadrilateral = 8.5 cm
Lengths of the perpendiculars dropped on it from the remaining opposite vertices are 3.5 cm and 4.5 cm.
To find:
The area of the quadrilateral.
Solution:
Diagonal divides the quadrilateral in 2 triangles. If diagonal is the base of both triangles then the lengths of the perpendiculars dropped on it from the remaining opposite vertices are heights of those triangles.
According to the question,
Triangle 1 : Base = 8.5 cm and Height = 3.5 cm
Triangle 2 : Base = 8.5 cm and Height = 4.5 cm
Area of a triangle is

Using this formula, we get


and


Now, area of the quadrilateral is



Therefore, the area of the quadrilateral is 34 cm².
22:6 is one of them. Do you need more than one?
Answer:
5/2
Step-by-step explanation:
Shown in picture above.
Answer:
6.
Step-by-step explanation:
Answer:
X = -5
Step-by-step explanation:
-6x + 18 = 7 - (4x + 9)
first we simplify the parentheses.
distribute the invisible number one created by the negative sign in front of the parentheses to get -6x + 18 = 7 - 4x - 9
then simplify further by subtracting 9 from the right side, leaving you with
-6x + 18 = -2 - 4x
next, add 2 to both sides to isolate the variable.
-6x + 20 = -4x
then, to isolate the variable further add 6x to both sides.
20 = -4x
divide both sides by -4 to isolate the variable
-5 = x
so, x = -5