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sleet_krkn [62]
2 years ago
11

7.1 Project Guidelines 2021

Physics
1 answer:
Ede4ka [16]2 years ago
3 0
I’m not sure if this will help but I found: https://prezi.com/l0fa6du3b9kp/going-off-the-grid-assignment/?fallback=1 and
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A 16 N force is applied to an object and 96 J of work is done. How far was the object moved?
ipn [44]
Your answer would be A. You divide 96 by 16 to find the answer
3 0
3 years ago
Read 2 more answers
A horse travels 80 meters south in 20 seconds. What is its average velocity?
AURORKA [14]

Average velocity is a vector unit (i.e. includes magnitude <em>and </em>direction) calculated by working out distance ÷ time:

80 metres ÷ 20 seconds = 4 metres/seconds (m/s)

Therefore, your final answer is C. 4 m/s south.

7 0
3 years ago
How do you know the speed of an electromagnetic wave in a vacuum?
ycow [4]
Electromagnetic waves need no matter to travel - they can travel through empty space (a vacuum). In a vacuum, all electromagnetic waves travel at approximately 3 x 108 m/s - which is the fastest speed possible. ...
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5 0
3 years ago
A box with a mass of 2 kg accelerates in a straight line
mihalych1998 [28]

Answer: 16N

Explanation:

Given that:

mass of box M= 2 kg

Initial speed V1 = 4 m/s

Final speed V2 = 8 m/s

Time taken T= 0.5 s

Average strength of this force F = ?

Now, recall that Force is the rate of change of momentum per unit time

i.e Force = momentum / time

Hence, F = M x (V2 - V1)/T

F = 2kg x (8 m/s - 4 m/s) / 0.5s

F = 2kg x (4 m/s / 0.5s)

F = 2kg x 8 m/s/s)

F = 16N

Thus, the average strength of this

force is 16 newton.

7 0
3 years ago
An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 2010 × 103 seconds (about
vazorg [7]

Answer:

Radial acceleration of moon is a_{r} = 2.246\times 10^{-3}\frac{m}{s^{2} }

Explanation:

Given :

Time period T = 1.987 \times 10^{6} sec

Distance from center of moon to planet r = 225 \times 10^{6} m

From the equation of radial acceleration,

  a_{r} = r\omega ^{2}

Where \omega = 2\pi f = \frac{2\pi }{T}

So   \omega = 3.16 \times 10^{-6} \frac{rad}{s}

Now moon's radial acceleration,

 a_{r} = 225 \times 10^{6} \times (3.16 \times 10^{-6} )^{2}

 a_{r} = 2246.76 \times 10^{-6}

 a_{r} = 2.246\times 10^{-3} \frac{m}{s^{2} }

7 0
3 years ago
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