How many electrons does eaach shell hold?

For this problem, the applied force P must be calculated such that the allowable stress of 180 MPa is not exceeded in either wir

Maru [420]

Answer:

we do not exceed that value, the force of having a value less than that calculated

Explanation:

Pressure is defined by

P = F / A

F = P A

F = 180 10⁶ A

for an exact calculation the area of the wire is needed

So that we do not exceed that value, the force of having a value less than that calculated

therefore the correct answer is "a smaller value"

4 0

3 years ago

A coffee cup calorimeter is prepared, containing 100.000 g of water (specific heat capacity = 4.184 J/g K) at initial temperatur

BARSIC [14]

Answer : The molar heat of solution for the salt is 452.9 kJ/mole

Explanation :

First we have to calculate the heat of solution.

$q=m\times c\times \Delta T$

where,

q = heat of solution = ?

c = specific heat of water = specific heat of solution = $4.184J/g.K=4.184J/g^oC$

m = mass of solution = 107.093 g

Mass of solution = Mass of water + Mass of salt
Mass of solution = 100.000 g + 7.093 g = 107.093 g

$\Delta T$ = change in temperature = $T_2-T_1=(80.000-61.128)=18.872^oC=$

Now put all the given values in the above formula, we get:

$q=107.093g\times 4.184J/g^oC\times 18.872^oC$

$q=8456.111J=8.456kJ$

Now we have to calculate the molar heat of solution for the salt, in kJ/mol.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = molar heat of solution = ?

q = heat required = 8.456 kJ

m = mass of salt = 7.093 g

Molar mass of salt = 379.984 g/mol

$\text{Moles of salt}=\frac{\text{Mass of salt}}{\text{Molar mass of salt}}=\frac{7.093g}{379.984g/mole}=0.01867mole$

$\Delta H=\frac{8.456kJ}{0.01867mole}=452.9kJ/mole$

Therefore, the molar heat of solution for the salt is 452.9 kJ/mole

4 0

3 years ago

The linear density of a rod of length 4 m is given by rho(x) measured in kilograms per meter, where x is measured in meters from

Elden [556K]

Answer:

50.67

Explanation:

L = 4 m

$\rho (x)=10+2\sqrt{x}$

Let the mass of small length dx is dm.

So, dm = ρ(x) dx

Integrate on both the sides within proper limits

$\int dm = \int \rho (x)dx=\int_{0}^{4}\left (10+2\sqrt{x} \right )dx$

$m = \left [ 10x+\frac{4}{3}x^{\frac{3}{2}} \right ]_{0}^{4}$

m = 40 + 32 / 3 = 152 / 3 = 50.67

6 0

4 years ago

The circuit below shows a silicon based transistor incorporated with a potential decider circuit to control the transistor. Dete

Kazeer [188]

Answer:

757.14 (2.d.p.)

Explanation:

CHECK THE IMAGE!! DEATHNOTE AT YOUR SERVICE. 12th Year Physics Kind Of Sucks!

7 0

3 years ago

An Amtrak going 250m/s comes to a stop in 12s. What is the<br> acceleration?

astraxan [27]

Answer:

$a=\frac{v-u}{t} \\a = \frac{0-250}{12} = -20.83 m/s$

Explanation:

you mean deceleration right ? because the acceleration is 250m/s

7 0

3 years ago