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3 years ago

Type of pulley that has additional numbers of ropes that help to increase mechanical advantage

1 answer:

4 0

Type of pulley that has additional numbers of ropes that help to increase mechanical advantage is a: C. Movable pulley

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_SeC16+_O2>_SeO2+_C12

juin [17]

Answer:

SeC14

Explanation:

sec14>C12-O

but since you can't subtract o from c , you get this

7 0

3 years ago

Differentiate convection and conduction class 7

BARSIC [14]

Answer:

While conduction is the transfer of heat energy by direct contact, convection is the movement of heat by actual motion of matter

Explanation:

5 0

3 years ago

Nicholas paddles his canoe downstream from the lodge to the park in 44 hours and then back upstream to the lodge in 55 hrs. If t

grandymaker [24]

Answer:

Nicholas' speed: 61.9772 miles/hour

current's speed: 6.8864 miles/hour

Explanation:

Let's call Nicholas's speed "x", and the current speed "y".

Going downstream, the total speed is x+y, and we can formulate the equation:

(x+y)*44 = 3030 -> x+y = 68.8636 miles/hour

Going upstream, the total speed is x-y, and we can formulate the equation:

(x-y)*55 = 3030 -> x-y = 55.0909 miles/hour

If we sum both equations, we have that:

2x = 123.9545

x = 61.9772 miles/hour

Now, to know the current speed, we just apply "x" value in one of the equations:

x+y = 68.8636 -> 61.9772 + y = 68.8636 -> y = 6.8864 miles/hour

8 0

4 years ago

A 2300 kg sailboat is moving west at 5.5 m/s when an eastward wind

pogonyaev

The boat is initially at equilibrium since it seems to start off at a constant speed of 5.5 m/s. If the wind applies a force of 950 N, then it is applying an acceleration a of

950 N = (2300 kg) a

a = (950 N) / (2300 kg)

a ≈ 0.413 m/s²

Take east to be positive and west to be negative, so that the boat has an initial velocity of -5.5 m/s. Then after 11.5 s, the boat will attain a velocity of

v = -5.5 m/s + a (11.5 s)

v = -0.75 m/s

which means the wind slows the boat down to a velocity of 0.75 m/s westward.

5 0

3 years ago

A centrifuge used in DNA extraction spins at a maximum rate of 7000rpm producing a "g-force" on the sample that is 6000 times th

defon

Answer:

A) a = 73.304 rad/s²

B) Δθ = 3665.2 rad

Explanation:

A) From Newton's first equation of motion, we can say that;

a = (ω - ω_o)/t. We are given that the centrifuge spins at a maximum rate of 7000rpm.

Let's convert to rad/s = 7000 × 2π/60 = 733.04 rad/s

Thus change in angular velocity = (ω - ω_o) = 733.04 - 0 = 733.04 rad/s

We are given; t = 10 s

Thus;

a = 733.04/10

a = 73.304 rad/s²

B) From Newton's third equation of motion, we can say that;

ω² = ω_o² + 2aΔθ

Where Δθ is angular displacement

Making Δθ the subject;

Δθ = (ω² - ω_o²)/2a

At this point, ω = 0 rad/s while ω_o = 733.04 rad/s

Thus;

Δθ = (0² - 733.04²)/(2 × 73.304)

Δθ = -537347.6416/146.608

Δθ = - 3665.2 rad

We will take the absolute value.

Thus, Δθ = 3665.2 rad

8 0

3 years ago