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german
3 years ago
10

Which of the following buffer systems would you use if you wanted to prepare a solution having a pH of approximately 9.5?Which o

f the following buffer systems would you use if you wanted to prepare a solution having a of approximately 9.5?
Chemistry
1 answer:
zalisa [80]3 years ago
7 0

Answer:

b. 0,08M NH₄⁺ / 0,12M NH₃

Explanation:

<em>The buffers are:</em>

<em>a. 0,08M H₂PO₄⁻ / 0,12M HPO₄²⁻</em>

<em>b. 0,08M NH₄⁺ / 0,12M NH₃</em>

It is possible to find out the pH of a buffer using Henderson-Hasselbalch formula:

<em>pH = pka + log₁₀ [A⁻] / [HA] </em><em>(1)</em>

Where A⁻ is the conjugate base of the weak acid, HA.

a. For the system H₂PO₄⁻ / HPO₄²⁻ pka is <u><em>7,198</em></u>. Replacing in (1)

pH = 7,198 + log₁₀ [0,12] / [0,08]

<em>pH = 7,37</em>

That means this buffer system don't have a pH of approximately 9,5

b. For the system NH₄⁺ / NH₃ pka is <em><u>9,3</u></em>. Replacing in (1)

pH = 9,3 + log₁₀ [0,12] / [0,08]

<em>pH = 9,50</em>

That means this buffer system is the buffer you need to use.

I hope it helps!

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For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0312 moles.

For Copper = \frac{0.0624}{0.0312}=2

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<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of Cu : S = 2 : 1

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