48.1 grams.
<h3>Explanation</h3>
How many moles of the reaction is needed to provide that 335 kJ of heat?
- ΔH = -824.2 kJ / mol according to the equation. In other words, each mole of the reaction releases 824.2 kJ of heat. (The value of ΔH is negative, which means that the reaction produces energy.)
- 335 / 842.2 = 0.4307 mol. It takes 0.4307 moles of the reaction <em>shown in the equation</em> to produce all the 335 kJ of heat.
How many moles of iron, Fe in 0.4307 moles of the reaction?
- The coefficient in front of Fe in the equation is two. As a result, each mole of this reaction would consume two moles of Fe. The 0.4307 moles of the reaction will consume 2 × 0.4307 = 0.861 moles of Fe to produce 335 kJ of heat.
What's the mass of 0.8614 moles of iron, Fe?
- Refer to a modern periodic table, the relative atomic mass of iron Fe is 55.85. As a result, the mass of one mole of iron Fe is 55.85 grams.
- 0.861 × 55.85 = 48.1 grams. Therefore, it takes 48.1 grams of iron to provide 335 kJ of heat through this reaction.
WHAT IS AN IONIC BOND
kossel explained that inert gases r inert due to the electronic configuration which contains 8 electrons in their outermost shell
And other elements loss and gain electrons to form ions and to have electronic configuration same as Noble gas and to get stable
#SARDAR JI.
<span>a) Oxidation state of Ba in reactant: 0
In product: +2.
</span><span>Oxidation state of Zn in reactant: +2.
In product: 0.
</span><span>Oxidation state of S in reactant: +6
In product: +6.
</span><span>Oxidation state of O in reactant: -2.
In product: -2.
This is redox reaction because elements change their oxidation states (barium and zinc).
</span>b) Oxidation reaction: Ba⁰ → Ba²⁺ + 2e⁻.
Reduction reaction: Zn²⁺ + 2e⁻ → Zn⁰.
c) Barium is oxidized (increase of oxidation number) and zinc is reduced (decrease of oxidation number).
d) <span> The oxidizing agent is zinc (gain electrons) and the reducing agent is barium (lose electrons).</span>
A theory fits all three of these descriptions. you can test, predict, and prove or disprove a theory. hope this helps!