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Oksanka [162]
3 years ago
15

Find the equation of the axis of symmetry for the parabola y=x^2-6x+41/5

Mathematics
1 answer:
ivolga24 [154]3 years ago
3 0

Answer:

x = 3

Step-by-step explanation:

given a parabola in standard form : y = ax² + bx + c : a ≠ 0

Then the equation of the axis of symmetry is

x = - \frac{b}{2a}

y = x² - 6x + \frac{41}{5} is in standard form

with a = 1 and b = - 6, hence

x = - \frac{-6}{2} = 3

equation of axis of symmetry is x = 3


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