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Ludmilka [50]
2 years ago
10

It is reported in USA Today that the average flight cost nationwide is $445.99. You have never paid close to that amount and you

want to perform a hypothesis test that the true average is actually greater than $445.99. What are the appropriate hypotheses for this test
Mathematics
1 answer:
nlexa [21]2 years ago
5 0

Answer:

H_0 : \mu \leq 445.99

H_a : \mu > 445.99

Step-by-step explanation:

It is given the average cost of the flight nationwide is $ 445.99

I wanted to \text{perform the hypothesis test} to determine that the true average is greater than $ 445.99

Let the hypothesis that the true average is actually greater than $445.99

Therefore,

the \text{null hypothesis} for the test is :

H_0 : \mu \leq 445.99

And the alternate hypothesis is :

H_a : \mu > 445.99

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A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 335335 babies were​ born
strojnjashka [21]

Answer:

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 335, \pi = \frac{268}{335} = 0.8

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563

For the percentage:

Multiplying the proportions by 100.

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

7 0
3 years ago
Celeste studied 1.25 hours for her Math test. This was 0.5 hour less than she studied for her Science test. Use the following eq
Ostrovityanka [42]

Answer:

1.75 - 0.5 = 1.25

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If (x+3)divided by 3 = 9 what is x
defon

Answer:

x = 24

Step-by-step explanation:

Given that:

(x+3)/3 = 9

multiplying both sides by 3

(x+3) = 9*3

(x+3)= 27

Subtracting 3 from both sides

x= 27-3

x=24

I hope it will help you!

3 0
3 years ago
Read 2 more answers
Simplify.<br> +6 - 4 =<br><br><br> please help ..........
Step2247 [10]

Answer:

2

Step-by-step explanation:

it's literally 6-4 = 2

8 0
3 years ago
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A newspaper carrier has ​$6.40in change. he has two more quarters than dimes but five times as many nickels as quarters. how man
bekas [8.4K]
He has 11 quarters, 9 dimes, and 55 nickels.
11x.25=2.75
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55x.05=2.75
2.75+2.75+.9=6.4
4 0
3 years ago
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