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AnnyKZ [126]
3 years ago
14

Mr. Burnam decided to go hot air ballooning for his fortieth birthday. He launches from 6 feet above ground and then ascends 12

feet further. He didn't want to leave his wife behind, so he descends 20 feet to meet her. Where does mr. Burnam end up?
Mathematics
1 answer:
Anton [14]3 years ago
6 0

Answer:

  2 feet below the ground level at the place where he started.

Step-by-step explanation:

After he adds 12 feet of elevation to the 6 feet above ground level where he launched, Mr Burnam is 6+12 = 18 feet above the ground level where he launched.

If he descends 20 feet, he will be 18 -20 = -2 feet above the ground level where he launched. That is, he is 2 feet below the ground level where he launched. We hope the ground slopes downward somewhat so Mr Burnam is not buried in the ground at that point.

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Answer:

x=7

Step-by-step explanation:

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3 years ago
Identify the following sequences as arithmetic, geometric, or neither. For the arithmetic and geometric sequences, identify the
Lapatulllka [165]

Hence,

a. 12, 144, 1728,..  => Geometric

b. 0,5, 10, 15, 20, 25,...  => Arithmetic

c. 0,4, 16, 36, 64,...  => Neither arithmetic nor geometric

d. 1.5, 2.25, 3.375, 5.0625,... => Geometric

Step-by-step explanation:

In order to identify the sequence as geometric or arithmetic sequence, we find the common difference and common ratio of the sequence. If the common difference is same, it is an arithmetic sequence and if the common ratio is same the sequence is a geometric sequence

Common difference is the difference between consecutive terms of an arithmetic sequence and common ration is the ratio between two consecutive terms of a sequence

So,

<u>a. 12, 144, 1728,..</u>

Here,

a_1=12\\a_2=144\\a_2=1728

Common difference:

d=a_2-a_1 = 144-12 = 132\\=a_3-a_2 = 1728-144=1584

Common Ratio:

r=\frac{a_2}{a_1} =\frac{144}{12} = 12\\=\frac{a_3}{a_2}=\frac{1728}{144} =12

As the common ratio is same, the given sequence is a geometric sequence.

<u></u>

<u>b. 0,5, 10, 15, 20, 25,...</u>

Here,

a_1 = 0\\a_2 =5\\a_3 =10

Common difference:

d=a_2-a_1 = 5-0 = 5\\d=a_3-a_2 = 10-5 = 5

As the common difference is same, the given sequence is an arithmetic sequence

<u></u>

<u>c. 0,4, 16, 36, 64,...</u>

Here

a_1 = 0\\a_2 =4\\a_3 = 16\\a_4 = 36

Common Difference:

d= a_2-a_1 = 4-0 = 4\\a_3-a_2 = 16-4 = 12

<u></u>

Common Ratio:

r=\frac{a_2}{a_1} = \frac{4}{0} = Doesn't\ exist

Neither the common ratio nor common difference are same, so the given sequence is neither arithmetic nor geometric

<u>d. 1.5, 2.25, 3.375, 5.0625,...</u>

Here

a_1 = 1.5\\a_2 = 2.25\\a_3 = 3.375

<u></u>

Common Difference:

d=a_2-a_1 = 2.25-1.5 = 0.75\\a_3-a_2 =3.375-2.25 = 1.125[/tex]Common Ratio: [tex]r=\frac{a_2}{a_1} = \frac{2.25}{1.5}=1.5\\=\frac{a_3}{a_2} =\frac{3.375}{2.25}=1.5

As the common ratio is same, given sequence is geometric

Hence,

a. 12, 144, 1728,..  => Geometric

b. 0,5, 10, 15, 20, 25,...  => Arithmetic

c. 0,4, 16, 36, 64,...  => Neither arithmetic nor geometric

d. 1.5, 2.25, 3.375, 5.0625,... => Geometric

<u>Keywords: Sequence, Ratio</u>

<u>Learn more about sequences at:</u>

  • brainly.com/question/3783529
  • brainly.com/question/3799248

#LearnwithBrainly

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A discrete random variable involves two key factors ; discrete and randomness ; Hence, a discrete random variable should have a finite or countable Number of outputs or values. It should also stem from a random procedure. Here, the height of the next hundred babies is a random procedure as the next 100 babies in the region are unknown until Given birth too and as such all pregnant women have the chance of having their babies among. Since, we are dealing with exact height values which are countable (100), then we this is a discrete random variable.

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the large bag is 5/6 lb, the smaller bags will be 1/3 lb, so it should be 5/6 ÷ 1/3

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3 years ago
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24

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