Answer:
a. chemical contamination of streams ans rivers
d. adaptation
Answer:
Explanation:
Given that,
Bathysphere radius
r = 1.5m
Mass of bathysphere
M = 1.2 × 10⁴ kg
Constant speed of descending.
v = 1.2m/s
Resistive force
Fr = 1100N upward direction
Density of water
ρ = 1.03 × 10³kg/m³
The volume of the bathysphere can be calculated using
V = 4πr³ / 3
V = 4π × 1.5³ / 3
V = 14.14 m³
The Bouyant force can be calculated using
Fb = ρgV
Fb = 1.03 × 10³ × 9.81 × 14.14
Fb = 142,846.18 N
Buoyant force is acting upward
Weight of the bathysphere
W = mg
W = 1.2 × 10⁴ × 9.81
W = 117,720 N
Weight is acting downward
The net positive buoyant using resolving
Fb+ = Fb — W
Fb+ = 142,846.18 — 117,720
Fb+ = 25,126.18 N
The force acting downward is the weight of the submarine and it is equal to the positive buoyant force and the resistive force
W = Fb+ + Fr
W = 25,126.18 + 1100
W = 26,226.18
mg = 26,226.18
m = 26,226.18 / 9.81
m = 2673.4kg
Mass of submarine is 2673.4kg
Answer:
16.6N
Explanation:
Given parameters:
Mass of rocket = 2000g = 2kg
Acceleration = 8.3m/s²
Unknown:
Force acting on the rocket = ?
Solution:
The force acting on a body can be derived from the product of its mass and acceleration;
Force = mass x acceleration
Insert the parameters and solve;
Force = 2 x 8.3 = 16.6N
the formula for velocity is:
v= distance/time
distance= 80m
time=2 seconds
v=80/2
v=40ms-1