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gizmo_the_mogwai [7]
3 years ago
12

How do I count 10 raised to minus numbers? (Ignore the text in the picture)

Mathematics
1 answer:
marishachu [46]3 years ago
6 0

The answer is 10000.001

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If 2^(x+3) - 2x = k(2^x) what is the value of k
svlad2 [7]

Answer:

\large\boxed{C)\ 7}

Step-by-step explanation:

Use:

a^n\cdot a^m=a^{n+m}

2^{x+3}-2^x=2^x\cdot2^3-2^x=8\cdot2^x-2^x=(8-1)\cdot2^x=7\cdot2^x\\\\2^{x+3}-2^x=k(2^x)\\\\7\cdot2^x=k(2^x)\Rightarrow k=7

8\cdot2^x-2^x=8\cdot2^x-1\cdot2^x=(8-1)(2^x)=7\cdot2^x\\\\\text{distributive property:}\ a(b-c)=ab-ac

8 0
3 years ago
The geometic mean of 4 and 21
-Dominant- [34]

Answer:

12.5

Step-by-step explanation:

4+21=25

25/2=12.5

4 0
2 years ago
Seven and thirty twp hundreths plus two and one tenth times two and seven tenths minus 18a
alexdok [17]
Answer:  Write the expression as:

" 70 \frac{32}{100} +
                         2\frac{1}{10} * 2\frac{7}{10 − 18a " ; 
______________________________________________________
or;  write as:
______________________________________________________
           " 70.32  + (2.1) * (2.7)  − 18a " ; 
______________________________________________________

To simplify:
______________________________________________________

  Using "PEDMAS" (the "order of operations") ; 

the "multiplication" comes first; 

So:  →  "(2.1) * (2.7) =  5.67 " .

And rewrite:
______________________________________________________
 " 70.32  + 5.67 − 18a " .

Now:  " 70.32 + 5.67 = 75.99 " ; 

So, we can the final simplified expression as:
______________________________________________________
   " 75.99  −  18a " ;  

or; write as:  " 75\frac{99}{100}  −  18a " .
______________________________________________________
7 0
3 years ago
$6.23 + $4.36 + $3.62 + $2.19 + $3.50 + $2.99 + tip: $3.43, + tax: $1.60
Lisa [10]
The answer is $27.92
5 0
2 years ago
If (a+b)=4 and ab=3 find the value of a3 +b3<br>​
elena-14-01-66 [18.8K]
I think this might be the answer since (a+b) equals 4, and ab= 3. I'm not sure.
a3 + b3
= (4)3+4(3)
= 12+12
= 24
5 0
2 years ago
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