The rule is +4
how did you find it you can 87-91=4
so that is your rule +4
<span>Turn the percent to a decimal by moving the decimal point over 2 places to the left. then multiply. so, 1425 * 375</span> = 53.44
Answer:
see the explanation
Step-by-step explanation:
we have
0.888...
This is a <u>repeating decimal</u> (Is a decimal that has a digit, or a block of digits, that repeat over and over and over again without ever ending)
Convert to fraction number
Let
x=0.888...
10x=8.888...
Subtract 0.888... from 8.888... to remove the decimal
10x-x=8.888...-0.888...
9x=8
Solve for x
x=8/9
therefore
Mike fraction is incorrect
because 4/5=0.8
0.8 is a <u>terminating decimal </u>(It's a decimal with a finite number of digits)
Mike's mistake was considering the number as a terminating decimal instead of a repeating decimal
Beth is correct
because
If you divide 8/9
the result is 0.8888888...
Ok so
ratio
35/200=x/3000
7/40=x/3000
multiply both sides by 12000
2100=4x
divide both sides by 4
525=x
aprox 525 people
Answer:
16.34 hours
Step-by-step explanation:
According to the given information we can see that the case is of exponential growth
Hence, we will use the formula

Here A =800 is the amount that is needed to reach
P is the initial amount that is 500
We have to find the time it will take to reach 800 that is we need to find t
On substituting the values in the formula we get

On simplification we get

Taking log on both sides we get

using 
And 

Now substituting values of log 8=0.903, log 5=0.698 and log 2=0.301 we get



