<span>4.8 (x+4)=2.6
Use distributive property
4.8x + 19.2= 2.6
Subtract 19.2 from both sides
4.8x = -16.6
Divide 4.8 on both sides so that the only thing remaining on the left side is the variable x.
Final Answer: x = -3.458</span>
Answer is C but if its on grad point your answer is 0.5(2)^x
Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56


fts
Now using Formula for time and range as

Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,


T is approximately equals to 4 sec.
Answer:
Step-by-step explanation:
Answer: y=2x+14
Explanation:
Y=mx+b
Y= 2x-4
M=2
Y= 2x+b
2 = (2 x -6) + b
2=-12+b
12+2=12+b
-12
14=0+b
14=b
Y=2x+14