We need to use the ideal gas formula. P1V1/T1= P2V2/T2
P1= 725 torr
V1= 550 mL
T1= 63 C= 336 K
P2= ?
V2= 376 mL
T2= 12 C= 285 K
(725 x 550)/(336)= (P2 x 376)/ (285K)
1190 = P2 x 1.32
P2= 900 torr
Answer:
HCl is the limiting reactant.
Explanation:
The reactant that yields the lesser number of moles of product is the limiting reactant
Number of moles of MnO2= mass of MnO2/ molar mass of MnO2
Number of moles= 37.7g/86.9368 g/mol= 0.4336 moles
From the reaction equation,
If 1 mole of MnO2 yields 1 mole of chlorine gas
0.4336 moles of MnO2 also yield 0.4336 moles of chlorine gas
For HCl
Number of moles of HCl= mass of HCl/ molar mass of HCl
Number of moles= 46.3g/36.46 g/mol = 1.27 moles of HCl
If 4 moles of HCl yields 1 mole of chlorine gas
1.27 moles of HCl will yield 1.27×1/4 = 0.3175 moles of HCl
Hence HCl is the limiting reactant.
Answer:
ΔS=0.148 KJ/K
Explanation:
Given that
Q = 100 KJ
T₁=200°C
T₁=200+273 = 437 K
T₂=5°C
T₂=5 + 273 = 278 K
Reservoir 1 is rejecting heat that is why it taken as negative while the reservoir 2 is gaining the heat that is why it is taken as positive.
So the total change in entropy given as
ΔS= - Q/T₁ + Q/T₂
ΔS= - 100/473 + 100/278 KJ/K
ΔS=0.148 KJ/K
Answer:
ok horita te ayudo ok esperame okey bueno