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erastovalidia [21]
4 years ago
5

The molar mass of O2 is 32.00 g/mol. How many moles of HgO are needed to produce 250.0 g of O2?

Chemistry
1 answer:
mote1985 [20]4 years ago
6 0

the moles would be 7.8125

divide 250g/32g/mol= 7.8125

Its a 1 to 1 mole ratio between O2 and HgO so they are the same number of moles.

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Diano4ka-milaya [45]
We need to use the ideal gas formula. P1V1/T1= P2V2/T2

P1= 725 torr
V1= 550 mL
T1= 63 C= 336 K
P2= ?
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T2= 12 C= 285 K

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1190 = P2 x 1.32

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3 0
4 years ago
Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide. 4HCl(aq)+MnO2(s)⟶M
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Answer:

HCl is the limiting reactant.

Explanation:

The reactant that yields the lesser number of moles of product is the limiting reactant

Number of moles of MnO2= mass of MnO2/ molar mass of MnO2

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From the reaction equation,

If 1 mole of MnO2 yields 1 mole of chlorine gas

0.4336 moles of MnO2 also yield 0.4336 moles of chlorine gas

For HCl

Number of moles of HCl= mass of HCl/ molar mass of HCl

Number of moles= 46.3g/36.46 g/mol = 1.27 moles of HCl

If 4 moles of HCl yields 1 mole of chlorine gas

1.27 moles of HCl will yield 1.27×1/4 = 0.3175 moles of HCl

Hence HCl is the limiting reactant.

8 0
3 years ago
Heat is transferred directly from a heat reservoir at 200 C to another heat reservoir at 5C. If the amount of heat transferred i
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Answer:

ΔS=0.148  KJ/K

Explanation:

Given that

Q = 100 KJ

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T₂=5 + 273 = 278 K

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So the total change in entropy given as

ΔS=  - Q/T₁ + Q/T₂

ΔS=  - 100/473 + 100/278  KJ/K

ΔS=0.148  KJ/K

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4 years ago
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Answer:

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3 years ago
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A chemist has dissolved a certain substance in water. The chemist knows that more of the substance could be dissolved into the w
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