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konstantin123 [22]
2 years ago
10

A chemist has dissolved a certain substance in water. The chemist knows that more of the substance could be dissolved into the w

ater before it stops dissolving. Therefore, the current solution is
.
Chemistry
2 answers:
STALIN [3.7K]2 years ago
8 0

Answer is: the current solution is unsaturated.

Unsaturated solution means that more of a substance can be dissolve.

For example:

Solubility of potassium chlorate (KClO₃) at 100 grams of water at 80°C is 37.5 g, that means that all 37.5 g is completely dissolves, this is the saturated solution.

If we add 20 grams of potassium chlorate in 100 grams of water, there is less solute than the saturated solution, so this is unsaturated solution.

FrozenT [24]2 years ago
5 0
Unsaturated………. The answer
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A reaction of 41.9 g of Na and 30.3 g of Br2 yields 36.4 g of NaBr . What is the percent yield?
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Answer: The percent yield is, 93.4%

Explanation:

First we have to calculate the moles of Na.

\text{Moles of Na}=\frac{\text{Mass of Na}}{\text{Molar mass of Na}}=\frac{41.9g}{23g/mole}=1.82moles

Now we have to calculate the moles of Br_2

{\text{Moles of}Br_2} = \frac{\text{Mass of }Br_2 }{\text{Molar mass of} Br_2} =\frac{30.3g}{160g/mole}=0.189moles

{\text{Moles of } NaBr} = \frac{\text{Mass of } NaBr }{\text{Molar mass of } NaBr} =\frac{36.4g}{103g/mole}=0.353moles

The balanced chemical reaction is,

2Na(s)+Br_2(g)\rightarrow 2NaBr

As, 1 mole of bromine react with = 2 moles of Sodium

So, 0.189 moles of bromine react with = \frac{2}{1}\times 0.189=0.378 moles of Sodium

Thus bromine is the limiting reagent as it limits the formation of product and Na is the excess reagent.

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So, 0.189 moles of bromine give = \frac{2}{1}\times 0.189=0.378 moles of Sodium bromide

Now we have to calculate the percent yield of reaction

\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100=\frac{0.353 mol}{0.378}\times 100=93.4\%

Therefore, the percent yield is, 93.4%

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3 years ago
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