Ask question

Ask question

All categories

4 years ago

11

Use the formula C = 2πr and π= 3.14 to find the circumference of a circle with a radius of 5 meters.

1 answer:

professor190 [17]4 years ago

7 0

Solution D

Just put into a calculator

Hope I helped :)

You might be interested in

Find the area of a trapezoid please help im so lost

Murrr4er [49]

Here, trapezoid is composed of two triangles, and one rectangle.
So, Area of rectangle = 4 * 7 = 28 cm²
Area of a triangle = 1/2 * 3 * 7 = 21/2 = 10.5 cm²

Area of Trapezoid = area of rectangle + 2(area of triangle)
= 28 + 2(10.5)
= 28 + 21 = 49

In short, Your Answer would be 49 cm²

Hope this helps!

5 0

3 years ago

What number can be used to complete the volume statement for the cone below?

saul85 [17]

Volume =16.89cm squares

8 0

3 years ago

Look at the triangles shown below.

Sophie [7]

Answer:

Variant c

Step-by-step explanation:

c²=4*9

c=6

You can apply phyphagor

b²=6²+9²=36+81=117

$3 \sqrt{13}$

4 0

3 years ago

Find the surface area of the figure.<br> PLEASE HELP!

olya-2409 [2.1K]

Answer:

The total surface area is: 468 in^2 which agrees with answer a)

Step-by-step explanation:

The three lateral faces of the prism are rectangles, and the sums of their areas give:

12 * 10 + 9 * 10 + 15 * 10 = 360 in^2

The area of each triangular base (notice it is a right triangle) is given by:

9 * 12 / 2 = 54 in^2, so we add TWO of these to the three rectangular faces:

Total surface = 360 in^2 + 2 * 54 in^2 = 468 in^2

6 0

3 years ago

You decide to enter in a rowing competition. To train, you go to the boat house and begin rolling down stream. You row for the s

fredd [130]

Answer:

Time spent rowing down stream $=100\ seconds$

Speed of boat in still water $=14\ ms^{-1}$

Step-by-step explanation:

Let speed of boat in still water be $= x\ ms^{-1}$

Speed of current $= 10\ ms^{-1}$

Speed of boat down stream = $\textrm{Speed of boat in still water +Speed of current}= (x+10)\ ms^{-1}$

Distance rowed down stream = 2400 m

Time spent rowing down stream = $\frac{Distance}{Speed}=\frac{2400}{x+10}\ s$ = $\frac{Distance}{Speed}=\frac{2400}{x+10}\ s$

Speed of boat up stream = $\textrm{Speed of boat in still water -Speed of current}= (x-10)\ ms^{-1}$

Distance rowed up stream = $\frac{1}{6} \textrm{ of distance rowed downstream}=\frac{1}{6}\times 2400 = 400\ m$

Time spent rowing up stream = $\frac{Distance}{Speed}=\frac{400}{x-10}\ s$

We know that,

$\textrm{Time spent rowing down stream =Time spent rowing up stream}$

So,

$\frac{2400}{x+10}=\frac{400}{x-10}$

Cross multiplying

$2400(x-10)=400(x+10)$

Dividing both sides by $400$

$\frac{2400(x-10)}{400}=\frac{400(x+10)}{400}$

$6(x-10)=x+10$

$6x-60=x+10$

Adding 60 to both sides.

$6x-60+60=x+10+60$

$6x=x+70$

Subtracting both sides by $x$

$6x-x=x+70-x$

$5x=70$

Dividing both sides by 5.

$\frac{5x}{5}=\frac{70}{5}$

∴ $x=14$

Speed of boat in still water $=14\ ms^-1$

Time spent rowing down stream = $\frac{2400}{14+10}=\frac{2400}{24}=100\ s$

3 0

3 years ago