Question

29.4 mL of an CH3COOH solution were titrated with 18.5 mL of a 0.0175 m LiOH solution to reach the equivalence point. What is the molarity of the CH3COOH solution

Answer 1

Answer:

0.11 M

Explanation:

The computation of molarity of the CH3COOH solution is shown below:-

$M_2 = \frac{M_1V_1}{V_2}$

Where,

$M_1$ = Molarity of LioH = 0.0175

$V_1$ = Volume of LioH = 18.5 ml

$V_2$ = Volume of CH3COOH = 29.4 ml

Now, we will put the values into the formula

$= \frac{0.0175\times 18.5}{29.4}\\\\ = \frac{0.32375}{29.4}$

Which gives result

= 0.011 M

Therefore for computing the molarity of the CH3COOH solution we simply applied the above formula.