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3 years ago

What is the mass of 2.9 moles of calcium? Show all work!

Chemistry

1 answer:

4vir4ik [10]3 years ago

6 0

Answer:

the mass of 2.9 moles of calcium is 116 g

Explanation:

The computation of the mass of 2.9 moles of calcium is shown below

As we know that

Mole = mass ÷ molar mass

where,

Moles be 2.9

And, we know that the molar mass of calcium be 40g/mol

Now put the values to the above formula

2.9 = Mass ÷ 40

So, the mass would be

= 40 × 2.9

= 116 g

Hence, the mass of 2.9 moles of calcium is 116 g

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Answer:

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Antoine lavoisier is credited with the discovery of the law of conservation of mass. the law states that in a chemical reaction,

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2 years ago

A 0.4021-g sample of a purified organic acid was dissolved in water and titrated potentiometrically. A plot of the data revealed

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Answer:

The molar mass of the acid is 167.5 g/mol

Explanation:

A 0.4021-g sample of a purified organic acid was dissolved in water and titrated potentiometrically. A plot of the data revealed a single end point after 19.31 mL of 0.1243 M NaOH had been introduced. Calculate the molecular mass of the acid.

Step 1: Data given

Mass of the sample of a purified organic acid = 0.4021 grams

Molarity = 0.1243 M

Volume needed to reach the end point = 19.1 mL = 0.01931 L

Step 2: Calculate the number of moles NaOH

Moles NaOH = molarity NaOH * volume

Moles NaOH = 0.1243 M * 0.01931 L

Moles NaOH = 0.00240 moles

Step 3: Calculate moles of the acid

We'll need 0.00240 moles of acid to neutralize 0.00240 moles of NaOH ( it's a single end point)

Moles acid = 0.00240 moles

Step 4: Calculate molar mass of the acid

Molar mass = mass / moles

Molar mass = 0.4021 grams / 0.00240 moles

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3 years ago

A metalloid has properties of

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3 years ago

The concentration of a biomolecule insdie a rod-shaped prokaryotic cell is 0.0051 M. Calculate the number of molecule inside the

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<u>Answer:</u> The number of molecules inside the cell are $2.2\times 10^6$

<u>Explanation:</u>

We are given a prokaryotic cell, which is in the shape of rod or cylinder.

The equation used to calculate the volume of cylinder is:

$V=\pi r^2h$

where,

V = volume of cell = ?

r = radius of the celle = $\frac{d}{2}=\frac{1.7\mu m}{2}=0.85\mu m=8.5\times 10^{-7}m$ (Conversion factor: $1m=10^6\mu m$ )

h = length of the cell = $3.1\mu m=3.1\times 10^{-6}m$

Putting values in above equation, we get:

$V=(3.14)\times (8.5\times 10^{-7})^2\times 3.1\times 10^{-6}\\\\V=7.033\times 10^{-18}m^3$

To calculate the number of moles for given molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of biomolecule = 0.0051 M

Volume of solution = $7.033\times 10^{-18}m^3=7.033\times 10^{-15}L$ (Conversion factor: $1m^3=1000L$ )

Putting values in above equation, we get:

$0.0051M=\frac{\text{Moles of biomoleculel}}{7.033\times 10^{-15}L}\\\\\text{Moles of biomolecule}=(0.0051mol/L\times 7.033\times 10^{-15}L)=3.59\times 10^{-17}mol$

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules

So, $3.59\times 10^{-17}$ moles of a biomolecule will contain = $(3.59\times 10^{-17}\times 6.022\times 10^{23}=2.2\times 10^6$ number of molecules

Hence, the number of molecules inside the cell are $2.2\times 10^6$

5 0

3 years ago