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Rasek [7]
3 years ago
10

What is the mass of 2.9 moles of calcium? Show all work!

Chemistry
1 answer:
4vir4ik [10]3 years ago
6 0

Answer:

the mass of 2.9 moles of calcium is 116 g

Explanation:

The computation of the mass of 2.9 moles of calcium is shown below

As we know that

Mole = mass ÷  molar mass

where,

Moles be 2.9

And, we know that the molar mass of calcium be 40g/mol

Now put the values to the above formula

2.9 = Mass ÷ 40

So, the mass would be

= 40 × 2.9

=   116 g

Hence, the mass of 2.9 moles of calcium is 116 g

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Answer:

Explanation:

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4 0
3 years ago
7. True or False. Camouflage is a physical adaptation.
Kaylis [27]
7. true
8. false
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8 0
2 years ago
Which missing item would complete this alpha decay reaction?<br><br> 257/100 Fm= ________+4/2He
maria [59]

Answer: ₉₈²⁵³Cf

253 is a superscript to the left of the symbol, Cf, which represents the mass number, and 98 is a subscript to the left of the same symbol, which represents the atomic number.

Explanation:

1) The alpha decay equation shows that the isotope Fm - 257, whose nucleus has 100 protons and 157 neutrons, emitted an alpha particle (a nucleus with 2 protons and 2 neutrons).

2) Therefore:

i) the mass number decreased in 4, from 257 to 257 - 4 = 253.

2) the atomic number decreased in 2, from 100 to 100 - 2 = 98.

3) Hence the formed atom has atomic number 98, which is californium, Cf, and the isotope is californium - 253.

4) The item that completes the given alpha decay reaction is:

₉₈²⁵³ Cf.

5) The complete alfpha decay reaction is:

₁₀₀²⁵⁷ Fm → ₉₈²⁵³Cf + ₂⁴He

You can verify the mass balance:

257 = 253 + 4, and

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4 0
3 years ago
Read 2 more answers
The metal tantalum becomes superconducting at temperatures below 4.483 K. Calculate the temperature at which tantalum becomes su
masha68 [24]

Answer:

The correct answer is "-268.667°C".

Explanation:

Given:

Temperature,

= 4.483 K (below)

Now,

The formula of temperature conversion will be:

⇒ T(^{\circ} C)=T(K)-273.15

By putting the values, we get

⇒            =4.483-273.15

⇒            =-268.667^{\circ} C

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3 0
3 years ago
The absorbance of an equilibrium mixture containing FeSCN2 was measured at 447 nm and found to be 0.347. What is the equilibrium
Ksenya-84 [330]

Answer:

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Explanation:

From the question we are told that

     The absorbance is  A = 0.347

       The length is  l =  447 nm  =  447 *10^{-7} \ cm

     

Generally absorbance is mathematically represented as

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where \epsilon is the molar absorptivity of  FeSCN2  with a value \epsilon  =  7.0*10^3 L/cm/mol

 and  C is the equilibrium concentration of FeSCN2

So  

       C = \frac{A}{\epsilon *  l  }

substituting values

        C = \frac{0.347}{7.0*10^{3} *  447 *10^{-7}  }

         C = 1.11 mol/L

5 0
3 years ago
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