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Lady_Fox [76]
4 years ago
5

Can someone please help with this ASAP :):):):):):):):):):):):):):)

Chemistry
1 answer:
GalinKa [24]4 years ago
7 0

Answer:

u just put T and t in all of the boxes

Explanation:

like this

T t

T t

and see how many times you get a dominant one which is 2 T T

i dont know if u understand I took this a long time ago i forgot my bad if it's hard to understand

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55.2 mL of 0.500 M potassium hydroxide is used to neutralize 27.4 mL of sulfuric
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Answer:

0.504 M

Explanation:

Step 1: Write the balanced neutralization reaction

2 KOH + H₂SO₄ ⇒ K₂SO₄ + 2 H₂O

Step 2: Calculate the reacting moles of KOH

55.2 mL (0.0552 L) of 0.500 M KOH react. The reacting moles of KOH are:

0.0552 L × 0.500 mol/L = 0.0276 mol

Step 3: Calculate the moles of H₂SO₄ that reacted with 0.0276 moles of KOH

The molar ratio of KOH to H₂SO₄ is 2:1. The reacting moles of H₂SO₄ are 1/2 × 0.0276 mol = 0.0138 mol

Step 4: Calculate the concentration of H₂SO₄

0.0138 moles of H₂SO₄ are in 27.4 mL (0.0274 L). The molarity of H₂SO₄ is:

[H₂SO₄] = 0.0138 mol/0.0274 L = 0.504 M

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