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kiruha [24]
3 years ago
13

If you had a mixture of ethanol, glycerol, ethylene glycol, methanol, and water, how could you separate these five substances ou

t from the mixture? Rank the compounds from first to last in terms of which will leave the solution. All these compounds dissolve into each other.
Chemistry
1 answer:
leonid [27]3 years ago
3 0

Fractional distillation

Explanation:

The best way to separate the mixtures out is through the process of fractional distillation.

In fractional distillation, liquid - liquid mixtures are separated based on the differences in boiling point of their components. Let us examine the boiling points of the component of the mixtures:  

     Ethanol                  78⁰C

     Glycerol                290⁰C

     Ethylene glycol     197.6⁰C

     Methanol               64.7⁰C

     Water                     100⁰C

We see that the liquids in the mixture have different boiling points. In this process, the mixture is heated in a distillation column. When the boiling point of any component is reached, it will rise up in the column and can be channeled to a condenser where it is cooled and collected.

The liquid with the least boiling point is first separated with the one with the highest boiling is recovered last:

   Order of recovery;

               Methanol               64.7⁰C

               Ethanol                  78⁰C

                Water                    100⁰C

               Ethylene glycol     197.6⁰C

                Glycerol                290⁰C

Learn more:

Physical properties brainly.com/question/10972073

#learnwithBrainly

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Answer:

Fórmula empírica: C₂H₂N

Fórmula molecular: C₄H₄N₂

Explanation:

Un compuesto que contiene carbono hidrógeno y nitrógeno con fórmula CₐHₓNₙ es sometido a combustion produciendo:

CₐHₓNₙ + O₂ → aCO₂ + x/2 H₂O + nNO₂

Con la masa de dióxido de carbono y agua podemos encontrar las moles de carbono e hidrógeno y su aporte a los 0.452g de muestra que fueron puestos en combustión, así:

<em>Moles C:</em>

Moles C = Moles CO₂ = 0.994g CO₂ ₓ (1mol / 44g) = 0.0226 moles C

Masa C: 0.0226 moles C ₓ (12.01g / mol) = 0.271g Carbono hay en la muestra

<em>Moles H:</em>

Moles H = 2 Moles H₂O = 0.203g H₂O ₓ (1mol / 18g) = 0.0113 moles H₂O = 0.0226 moles H

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Masa N = 0.158g Nitrógeno

Y su moles son:

0.158g ₓ (1 mol / 14.01g) = 0.0113 moles N

Con las moles de C, H y N podemos determinar la formula empírica que se define como: "La relación de números enteros más simple entre la cantidad de átomos presentes en una mólecula. Si usamos como base las moles de nitrógeno (Valor menor):

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Relación C/N: 0.0226 mol / 0.0113 mol = 2

Relación N/N: 0.0113 mol / 0.0113 mol = 1

Así, la <em>fórmula empírica es:</em>

<h3>C₂H₂N</h3>

Esta fórmula empírica tiene una masa molar de:

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2H = 2*1g/mol = 2g/mol

N = 14g/mol

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Como la masa molecular del compuesto es 80g/mol (Dos veces la de la fórmula empírica, la <em>fórmula molecular es 2 veces la fórmula empírica:</em>

<h3>C₄H₄N₂</h3>
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