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Sveta_85 [38]
3 years ago
13

Complete the balanced dissociation equation for the compound below. If the compound does not dissociate, write NR after the reac

tion arrow.
K2Cr2O7(s) â
Chemistry
1 answer:
nikdorinn [45]3 years ago
6 0

Answer:

K₂Cr₂O₇(s) ⇒ 2 K⁺(aq) + Cr₂O₇²⁻(aq)

Explanation:

Potassium dichromate (K₂Cr₂O₇) is a strong electrolyte, that is, when dissolved in water (the medium), it dissociates in cation potassium (K⁺) and anion dichromate (Cr₂O₇²⁻). The balanced dissociation equation is:

K₂Cr₂O₇(s) ⇒ 2 K⁺(aq) + Cr₂O₇²⁻(aq)

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How many protons and electrons are there in a neutral atom of lithium<br> Np=Ne
pantera1 [17]

Answer:

3 protons and also 3 electrons

Explanation:

z=p=e

3 0
3 years ago
This problem is from a New York Times article. Researchers tested a group of 28 doctors. The doctors were told that a 5-year-old
telo118 [61]

Answer:

0.12 mL of the epinephrine solution.

Explanation:

We have:

A bottle of epinephrine labeled 1 mg in 1 mL of solution,

We need to prepare:

An injection of 0.12 mg of epinephrine

Hence:

\frac{1 mL}{1 mg}*0.12 mg = 0.12 mL

Therefore, to prepare an injection of 0.12 mg of epinephrine labeled 1 mg in 1 mL we need to inject 0.12 mL of the epinephrine solution.          

I hope it helps you!

7 0
3 years ago
How many moles of coF3 are produced when 1.25 moles of 3co reacts
oee [108]

Answer:

1.25 moles

Explanation:

First, we need to balance the equation. Essentially, this means making sure we have the same number of each atom on each side.

On the left side, we currently have:

- 1 Co atom

- 2 F aomts

On the right side, we have:

- 1 Co atom

- 3 F atoms

To balance it, add a 2 to Co on the left, 3 to F2 on the left, and 2 to CoF3 on the right:

2Co+3F_2 → 2CoF_3

Now, we have 1.25 moles of Co, and since the ratio between Co and CoF3 is 1:1, we also have 1.25 moles of CoF3.

Thus, the answer is 1.25 moles.

7 0
4 years ago
Read 2 more answers
What affects the density of a substance? Select all that apply. Mass Gravity Volume Weight
Vlada [557]
Mass and Volume! 

Hope this helps. :)
7 0
3 years ago
Be sure to answer all parts. Find the pH during the titration of 20.00 mL of 0.1000 M triethylamine, (CH3CH2)3N (Kb = 5.2 × 10−4
Nataliya [291]

Answer:

(a) 10.62

(b) 2.82

(c) 1.95

Explanation:

The neutralization reaction in this question is

(CH3CH2)3N + HCl   ⇒ (CH3CH2)3NH⁺ + Cl⁻

The problem  can be  solved by calculating the number of moles of triethylamine after  addition of the portions of HCl. Since it is a weak base if it is not consumed completely, that is in excess we will have a buffer of a waek base. If its consumed completely the pH will be determined by the strong acid HCl.

The pOH for a buffer of a weak base is gven by

pOH = pKb + log [(CH3CH2)3NH⁺] / [(CH3CH2)3N]

(a) 11 mL of 0.100 M HCl

mol HCl = 0.011 L x 0.100 mol/L = 0.0011 mol HCl

mol  (CH3CH2)3N reacted = 0.0011 mol

mol (CH3CH2)3NH⁺ produced = 0.0011 mol

mol (CH3CH2)3N  initially = 0.020 L x 0.1000 mol/L 0.0020 mol

mol (CH3CH2)3N left = 0.0020 mol - 0.0011 = 0.0009 mol

pKb = - log Kb = - log (5.2 x 10⁻⁴) = 3.284

Now we can compute pOH,

pOH = 3.284 + log ( 0.0011 / 0.0009 ) = 3.37

pH = 14 - pOH = 14 - 3.37 = 10.62

(b) 20.60 mL HCl

mol HCl = 0.0206 L x 0.100 mol/L = 0.00206

mol  (CH3CH2)3N consumed = 0.0020 mol

This is so  because the acid will consume completely the 0.0020 mol of the weak base  we had originally present.

Now the problem circumscribes to that of calculating the pH of the unreacted HCl

Total Vol = 0.0206 L + 0.02 L = 0.0406 L

mol HCl = 0.0206 L x .100 = 0.00206 mol

mol HCl left = 0.00206 mol - 0.0020 mol = 0.00006 mol

[HCl] = 0.00006 mol / 0.0406 L = 0.0015 M

Since HCl is a strong acid ( 100 % ionization) :

pH = - log [H⁺] = - log ( 0.0015 ) = 2.82

(c) We will compute the pH in  the same way we did for part (b)

mol HCl = 0.025 L x 0.100 mol/L = 0.0025 mol

mol HCl left = 0.0025 mol  - 0.0020 mol = 0.0005

Total Volume = 0.020 L + 0.025 L = 0.045 L

[HCl] = 0.0005 mol / 0.045 L = 0.111

pH = - log ( 0.111) = 1.95                                            

3 0
3 years ago
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