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Hunter-Best [27]
3 years ago
10

Consider a sample of helium and a sample of neon, both at 30.0°C and 1.5 atm. Both samples have a volume of 5.0 liters. Which st

atement concerning these samples is not true? Consider a sample of helium and a sample of neon, both at 30.0°C and 1.5 atm. Both samples have a volume of 5.0 liters. Which statement concerning these samples is not true?
A) Each sample weighs the same amount.
B) The density of the neon is greater than the density of the helium.
C) Each sample contains the same number of atoms of gas.
D) Each sample contains the same number of moles of gas.
E) none of the above
Chemistry
1 answer:
Triss [41]3 years ago
7 0

Answer:

A.

Explanation:

Using the ideal gas equation, we can calculate the number of moles present. I.e

PV = nRT

Since all the parameters are equal for both gases, we can simply deduce that both has the same number of moles of gases.

The relationship between the mass of each sample and the number of moles can be seen in the relation below :

mass in grammes = molar mass in g/mol × number of moles.

Now , we have established that both have the same number of moles. For them to have the same mass, they must have the same molar masses which is not possible.

Hence option A is wrong

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The maximum number of electrons in a single d subshell is:
Iteru [2.4K]

10 electrons

Explanation:

The maximum number of electrons in a single d-subshell is 10 electrons.

The d-sub-orbital used to denote azimuthal or secondary quantum numbers.

The maximum number of electrons in the orbitals of sublevels are:

    two electrons in the s-sublevel, it has one orbital

   

   six electrons in the p-sublevel, it has three orbital

   ten electrons in the d- sublevel, it has five orbitals

   

   fourteen electrons in the f-sublevel, it has seven orbitals

The maximum number of electrons in an orbital is two.

learn more:

Atomic orbitals brainly.com/question/1832385

#learnwithBrainly

   

4 0
3 years ago
There are two stable isotopes of carbon, carbon -
nalin [4]

There is not enough information to determine anything about the relative abundances of the two isotopes.

<h3>What are isotopes?</h3>

Isotopes are atoms that have the same atomic number but different mass numbers. We know that all the isotopes of an element are not available to the same extent in nature.

Hence, from the average atomic mass of carbon, we can see that there is not enough information to determine anything about the relative abundances of the two isotopes.

Learn more about isotopes:brainly.com/question/11680817

#SPJ1

4 0
1 year ago
A wooden tool is found at an archaeological site. Estimate the age of the tool using the following information: A 100 gram sampl
lord [1]

Answer:

2578.99 years

Explanation:

Given that:

100 g of the wood is emitting 1120 β-particles per minute

Also,

1 g of the wood is emitting 11.20 β-particles per minute

Given, Decay rate = 15.3 % per minute per gram

So,

Concentration left can be calculated as:-

C left = [A_t]=\frac{11.20\ per\ minute}{15.3\ per\ minute\ per\ gram}\times [A_0]= 0.7320[A_0]

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Also, Half life of carbon-14 = 5730 years

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac {ln\ 2}{5730}\ years^{-1}

The rate constant, k = 0.000120968 year⁻¹

Time =?

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

So,  

\frac {[A_t]}{[A_0]}=e^{-0.000120968\times t}

\frac {0.7320[A_0]}{[A_0]}=e^{-0.000120968\times t}

0.7320=e^{-0.000120968\times t}

ln\ 0.7320=-0.000120968\times t

<u>t = 2578.99 years</u>

8 0
3 years ago
Determine the volume of a 0.800 M K2Cr2O7 solution required to completely react with 4.24 g of Cu.
Pachacha [2.7K]

<u>Answer:</u> The volume of solution required is 0.0275 L.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of copper = 4.24 g

Molar mass of copper = 63.55 g/mol

Putting values in above equation, we get:

\text{Moles of copper}=\frac{4.24g}{63.55g/mol}=0.067mol

The chemical equation for the reaction of potassium dichromate and copper follows:

K_2Cr_2O_7+3Cu+7H_2SO_4\rightarrow 3CuSO_4+Cr_2(SO_4)_3+K_2SO_4+7H_2O

By Stoichiometry of the reaction:

3 moles of copper reacts with 1 mole of potassium dichromate.

So, 0.067 moles of copper will react with = \frac{1}{3}\times 0.067=0.022mol of potassium dichromate

To calculate the volume of potassium dichromate, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

We are given:

Moles of potassium dichromate = 0.022 mol

Molarity of solution = 0.800 M

Putting values in above equation, we get:

0.08mol/L=\frac{0.022mol}{\text{Volume of solution}}\\\\\text{Volume of solution}=0.0275L

Hence, the volume of solution required is 0.0275 L.

6 0
2 years ago
Which of the following is fansition<br>metallon<br>Akt<br>02 라<br>Sfeet​
kow [346]

Answer: 02 라

Explanation:

5 0
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