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3 years ago

The molar mass of blood sugar, C6H12O6 also known as glucose and dextrose is

1 answer:

3 0

The molar mass is calculated by looking up the relative atomic mass values on a periodic table. The relative atomic mass is a value without units that is calculated on a Carbon-12 scale.

By looking at the periodic table (values will be to 3 significant figures [2 for hydrogen though]):
Molar mass (M) of 1 mole of Carbon = 12.0 g/mol
Molar mass (M) of 1 mole of Hydrogen = 1.0 g/mol
Molar mass (M) of 1 mole of Oxygen = 16.0 g/mol

So the molar mass is essentially the relative atomic mass (RAM), but molar mass has a unit, but RAM doesn't (it is a ratio).

Given the formula is C6H12O6 (without putting the numbers as subscripts), we can calculate as follows:
M (C6H12O6) = (6 x 12.0) + (12 x 1.0) + (6 x 16.0)
= 72.0 + 12.0 + 96.0
= 180.0 g/mol

Hope it's right :D

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i. The dissolution of PbSO₄ in water entails its ionizing into its constituent ions:

$\mathrm{PbSO_{4}}(aq) \rightleftharpoons \mathrm{Pb^{2+}}(aq)+\mathrm{SO_4^{2-}}(aq).$

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ii. Given the dissolution of some substance

$xA{(s)} \rightleftharpoons yB{(aq)} + zC{(aq)}$ ,

the Ksp, or the solubility product constant, of the preceding equation takes the general form

$K_{sp} = [B]^y [C]^z$ .

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$K_{sp} = \mathrm{[Pb^{2+}] [SO_4^{2-}]}$ .

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iii. Presumably, what we're being asked for here is the molar solubility of PbSO4 (at the standard 25 °C, as Ksp is temperature dependent). We have all the information needed to calculate the molar solubility. Since the Ksp tells us the ratio of equilibrium concentrations of PbSO4 in solution, we can consider either [Pb2+] or [SO4^2-] as equivalent to our molar solubility (since the concentration of either ion is the extent to which solid PbSO4 will dissociate or dissolve in water).

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