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kogti [31]
3 years ago
13

The molar mass of blood sugar, C6H12O6 also known as glucose and dextrose is

Chemistry
1 answer:
KIM [24]3 years ago
3 0
The molar mass is calculated by looking up the relative atomic mass values on a periodic table. The relative atomic mass is a value without units that is calculated on a Carbon-12 scale.

By looking at the periodic table (values will be to 3 significant figures [<em>2</em><em> for hydrogen though]</em>):
Molar mass (M) of 1 mole of Carbon = 12.0 g/mol
Molar mass (M) of 1 mole of Hydrogen = 1.0 g/mol
Molar mass (M) of 1 mole of Oxygen = 16.0 g/mol

So the molar mass is essentially the relative atomic mass (RAM), but molar mass has a unit, but RAM doesn't (it is a ratio).

Given the formula is C6H12O6 (without putting the numbers as subscripts), we can calculate as follows:
M (C6H12O6) = (6 x 12.0) + (12 x 1.0) + (6 x 16.0)
                       = 72.0 + 12.0 + 96.0
                       = 180.0 g/mol

Hope it's right :D
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In an organic structure, you can classify each of the carbons as follows: Primary carbon (1o) = carbon bonded to just 1 other ca
Alla [95]

The question is incomplete, complete question is :

In an organic structure, you can classify each of the carbons as follows: Primary carbon (1°) = carbon bonded to just 1 other carbon group Secondary carbon (2°) = carbon bonded to 2 other carbon groups Tertiary carbon (3°) = carbon bonded to 3 other carbon groups Quaternary carbon (4°) = carbon bonded to 4 other carbon groups How many carbons of each classification are in the structure below? How many total carbons are in the structure? How many primary carbons are in the structure? How many secondary carbons are in the structure? How many tertiary carbons are in the structure? How many quaternary carbons are in the structure?

Structure is given in an image?

Answer:

There are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.

Explanation:

Total numbers of carbon = 10

Number of primary carbons that is carbon joined to just single carbon atom = 6

Number of secondary carbons that is carbon joined to two carbon atoms = 1

Number of tertiary carbons that is carbon joined to three carbon atoms = 2

Number of quartenary carbons that is carbon joined to four carbon atoms = 1

So, there are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.

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3 years ago
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Answer:

plants take carbon dioxide out of the atmosphere and use the energy from sunlight to combine the carbon dioxide and water to form sugar and oxygen

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Zn(s) + 2HCl(aq) mc029-1.jpg H2(g) + ZnCl2(aq) Which product is a substance that is dissolved in solution?
nexus9112 [7]
The product that is dissolved in the solution would be the salt zinc chloride. It is a substance that is soluble in water so it should be dissolved in the solution. Also, from the reaction, the sign (aq) is written. It means that this substance is in aqueous solution.
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In which situation has the independent variable for the experiment been changed?
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The volume of a bubble that starts at the bottom of a lake at 4.55°C increases by a factor of 8.00 as it rises to the surface wh
Masja [62]

Answer:

The depth of the lake is 67.164 meters.

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas in bubble= ?

P_2 = final pressure of gas = 0.980 atm

V_1 = initial volume of gas = V

V_2 = final volume of gas = 8.00 × V

T_1 = initial temperature of gas = 4.55^oC=273.15+4.55=277.7 K

T_2 = final temperature of gas = 18.05^oC=273.15+18.05=291.2 K

Now put all the given values in the above equation, we get:

\frac{P_1\times V}{277.7 K}=\frac{0.980 atm\times 8.00\times V}{291.2 K}

P_1=7.476 atm

pressure of the gas in bubble initially is equal to the sum of final pressure and pressure exerted by water at depth h.

P_1=P_2+h\rho\times g

Where :

\rho = density of water = 1.00 g /cm^3=1000 g/m^3

g = acceleration due gravity = 9.8 m/s^2

7.476 atm=0.980 atm +h\rho\times g

6.496 atm=h\rho\times g

6.496 \times 101325 Pa=h\1000 g/m^3\times 9.8 m/s^2

h = 67.164 m

The depth of the lake is 67.164 meters.

4 0
3 years ago
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