Answer:
O3 is stronger oxidizing agent than HO2-.
Cl2 is stronger oxidizing agent than I2.
Zn^2+ is stronger oxidizing agent than Co^2+.
Br2 is stronger oxidizing agent than BrO3-.
Explanation:
An oxidizing agent oxidizes other compound by undergoing reduction itself.
Gaining of electron or hydrogen is reduction.
1. O3 is stronger oxidizing agent than HO2-. Because O3 readily gets decomposed into O2 and nascent (O), which oxidizes other compound. whereas as HO2- sometimes gets reduced to H2O2 and sometimes gets oxidized to O2.
2. Cl2 is stronger oxidizing agent than I2, as Cl2 can easily gain electrons compared to I2 due to its small atomic size.
3. Zn^2+ is stronger oxidizing agent than Co^2+, because Zn^2+ readily gains electrons compared toCo^2+ to form stable Zn due to its small atomic size.
4. Br2 is stronger oxidizing agent than BrO3-, as Br2 can accept electrons due to readily available empty orbitals compared to BrO3-.
The first thing you need to do with problem of this kind is to write the chemical equation. This would help you in calculations later. First, convert how many moles are there in 1.75g of carbon dioxide. Then, from the chemical equation you will know how many moles of sodium bicarbonate formed with 1 mole of carbon dioxide. Then convert the moles of sodium bicarbonate to grams using the molecular weight of the compound. You now have your answer.
Answer:
The power of yet is a way to change you mindset about something. It gives you a positive mindset, because it you say I cant do this yet. you are not giving up
Explanation:
Answer: partial pressure of NOBr is 7792 atm
Explanation:
Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.
Equilibrium constant is given as:
![K_{p}=\frac{[p_{NOBr}]^2}{[p_{NO}]^2\times [p_{Br_2}]^1}](https://tex.z-dn.net/?f=K_%7Bp%7D%3D%5Cfrac%7B%5Bp_%7BNOBr%7D%5D%5E2%7D%7B%5Bp_%7BNO%7D%5D%5E2%5Ctimes%20%5Bp_%7BBr_2%7D%5D%5E1%7D)
![28.4=\frac{[p_{NOBr}]^2}{[(119)^2\times (151)^1}](https://tex.z-dn.net/?f=28.4%3D%5Cfrac%7B%5Bp_%7BNOBr%7D%5D%5E2%7D%7B%5B%28119%29%5E2%5Ctimes%20%28151%29%5E1%7D)
![[p_{NOBr}]=7792](https://tex.z-dn.net/?f=%5Bp_%7BNOBr%7D%5D%3D7792)
atm
Partial pressure of NOBr is 7792 atm
