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Tems11 [23]
3 years ago
6

A certain material has a normal freezing point of 10ºC and a normal boiling point of 70ºC. What state is the material in at room

temperature (about 22ºC)? Explain your answer.
Chemistry
1 answer:
ahrayia [7]3 years ago
5 0

Explanation:

A freezing point is defined as the point in which a liquid state of a substance changes into solid state.

Whereas boiling point is defined as the point at which liquid state of substance starts to convert into vapor state.

So, a substance is freezing at 10^{o}C and boils at 70^{o}C then it means at room temperature, that is, around 25^{o}C the substance is present in liquid state.

This is because between the freezing and boiling point a substance will always exist in liquid state.

Thus, we can conclude that state of the material at room temperature is liquid.

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Watch the animation depicting Rutherford’s experiment and choose which of the following conclusions are correct.a. The atom cont
Lilit [14]

Answer:

a, b, c, d

Explanation:

Rutherford’ atomic model is based on the gold foil experiment. In this experiment, beam of alpha rays was bombarded on thin gold foil. He observed that:

Most of the alpha particles passed through thin foil without any deflection.

Few alpha particles deflected by an angle of 90o.

Based on observation, Rutherford concluded that majority of the space inside the atom is empty.

He explained defection of few alpha particles by assuming that most of the mass is concentrated at the nucleus and positively charged.  

Therefore, among given, the correct statements are:

The atom contains a positively charged nucleus.

Positive charge is condensed in one location within the atom.

The majority of the space inside the atom is empty space

The mass of an atom is concentrated at the nucleus

Therefore, the correct options are:

a, b, c, d

4 0
3 years ago
What is meant by chemical combination? what are the laws of chemical combination?​
balu736 [363]

Answer:

In simple terms, this law states that matter can neither be created nor destroyed. In other words, the total mass, that is, the sum of the mass of reacting mixture and the products formed remains constant.

Explanation:

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7 0
3 years ago
PLEASE HELP!!!!!!!!!
andreev551 [17]

The average atomic mass of the imaginary element : 47.255 amu

<h3>Further explanation  </h3>

The elements in nature have several types of isotopes  

Isotopes are elements that have the same Atomic Number (Proton)  

Atomic mass is the average atomic mass of all its isotopes  

Mass atom X = mass isotope 1 . % + mass isotope 2.% ..

isotope E-47 47.011 amu, 87.34%

isotope E-48 48.008 amu, 6.895

isotope E-49 50.009 amu, 5.77%

The average atomic mass :

\tt avg~mass=0.8734\times 47.011+0.06895\times 48.008+0.0577\times 50.009\\\\avg~mass=41.059+3.310+2.886\\\\avg~mass=47.255~amu

5 0
3 years ago
What does the large number in front of<br> the molecule represent?
madam [21]
A large number in front of a compound designates how many units there are of that compound. Parentheses can be used to designate a special structure, where other molecules are attached to the larger, complex molecule.
4 0
3 years ago
Read 2 more answers
5. Write a net ionic equation that occurs in a Na2HPO4/NaH2PO4 buffer solution when: A) a small amount of HCl is added (2 points
labwork [276]

Answer: (A) H_{3}O^{+}(aq) + HPO^{2-}_{4}(aq) \rightarrow H_{2}PO^{2-}_{4}(aq) + H_{2}O(l)

(B) H_{2}PO^{-}_{4}(aq) + OH^{-}(aq) \rightarrow HPO^{2-}_{4}(aq) + H_{2}O(l)

Explanation:

(A) As we know that HCl is a strong acid and when it is added to an aqueous solution then it leads to increase in the concentration of hydrogen ions. And, when an acid or base is added to a solution then any resistance by the solution in changing the pH of the solution is known as a buffer.

This means that addition of buffer into the given solution will not cause much change in the concentration of H_{3}O^{+} in large amount.

As both the buffer components are salt then they will remain dissociated as follows.

       Na_{2}HPO_{4}(aq) \rightarrow 2Na^{+}(aq) + HPO^{2-}_{4}(aq)

 NaH_{2}PO_{4}(aq) \rightarrow Na^{+}(aq) + H_{2}PO^{-}_{4}(aq)

Hence, net ionic equation will be as follows.

       H_{3}O^{+}(aq) + HPO^{2-}_{4}(aq) \rightarrow H_{2}PO^{2-}_{4}(aq) + H_{2}O(l)

(B)  When we add small amount of sodium hydroxide into the solution then there will occur an increase in concentration of hydroxide ions into the solution. But then due to the presence of buffer there will occur not much change in concentration and the acid will get converted into salt.

     NaOH(aq) \rightarrow Na^{+}(aq) + OH^{-}(aq)

The net ionic equation is as follows.

        H_{2}PO^{-}_{4}(aq) + OH^{-}(aq) \rightarrow HPO^{2-}_{4}(aq) + H_{2}O(l)

7 0
3 years ago
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