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Tems11 [23]
3 years ago
6

A certain material has a normal freezing point of 10ºC and a normal boiling point of 70ºC. What state is the material in at room

temperature (about 22ºC)? Explain your answer.
Chemistry
1 answer:
ahrayia [7]3 years ago
5 0

Explanation:

A freezing point is defined as the point in which a liquid state of a substance changes into solid state.

Whereas boiling point is defined as the point at which liquid state of substance starts to convert into vapor state.

So, a substance is freezing at 10^{o}C and boils at 70^{o}C then it means at room temperature, that is, around 25^{o}C the substance is present in liquid state.

This is because between the freezing and boiling point a substance will always exist in liquid state.

Thus, we can conclude that state of the material at room temperature is liquid.

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Write the name for the following molecular compounds. Remember to use the correct prefix for each compound.
Westkost [7]

Answer:

Hey there!

CS2) Carbon Disulfide.

PBr3) Phosphorus Tribromide

NO) Nitric Oxide

CF4) Carbon Tetrafluoride

P2O5) Phosphorus Pentoxide

Let me know if this helps :)

3 0
3 years ago
BRAINLIEST IF CORRECT
Tpy6a [65]

Answer:

Explanation:

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6 0
3 years ago
An airplane model is an example of what type of model
Ksju [112]
TL;DR: The make of an aircraft is the name of the designer (for example, Boeing) and the model of an aircraft (also called the type) is the designation for the general design of the aircraft (for example, 737). It looks like "basic model" is just an older term for "model".
7 0
3 years ago
How many milliliters of a 0.285 M HCl solution are needed to neutralize 249 mL of a 0.0443 M Ba(OH)2 solution?
meriva

Answer:

\large \boxed{\text{77.4 mL}}

Explanation:

                Ba(OH)₂ + 2HCl ⟶ BaCl₂ + H₂O

    V/mL:     249

c/mol·L⁻¹:  0.0443     0.285

1. Calculate the moles of Ba(OH)₂

\text{Moles of Ba(OH)$_{2}$} = \text{0.249 L Ba(OH)}_{2} \times \dfrac{\text{0.0443 mol Ba(OH)}_{2}}{\text{1 L Ba(OH)$_{2}$}} = \text{0.011 03 mol Ba(OH)}_{2}

2. Calculate the moles of HCl

The molar ratio is 2 mol HCl:1 mol Ba(OH)₂

\text{Moles of HCl} = \text{0.011 03 mol Ba(OH)}_{2} \times \dfrac{\text{2 mol HCl}}{\text{1  mol Ba(OH)}_{2}} = \text{0.022 06 mol HCl}

3. Calculate the volume of HCl

V_{\text{HCl}} = \text{0.022 06 mol HCl} \times \dfrac{\text{1 L HCl}}{\text{0.285 mol HCl}} = \text{0.0774 L HCl} = \textbf{77.4 mL HCl}\\\\\text{You must add $\large \boxed{\textbf{77.4 mL}}$ of HCl.}

8 0
3 years ago
Write the chemical equation that represents the process of lattice energy for the case of nacl.
faust18 [17]

Answer: Na^+(g)+Cl^-(g)\rightarrow NaCl(s),\Delta H_{Lattice}=-786kJ/mol

Explanation:

Lattice energy : It is defined energy released when ions combine together in a gaseous phase to form a compound. it is energy possessed by the crystal lattice of a compound. Denoted by symbol \Delta H_{Lattice}.

\Delta H_{Lattice}=positive , energy is absorbed while forming of the lattice

\Delta H_{Lattice}=negative, energy is release while forming of the lattice

Na^+(g)+Cl^-(g)\rightarrow NaCl(s),\Delta H_{Lattice}=-786kJ/mol

One mole of sodium ion when combines with one mole chloride ion release  786 kJ of energy.

4 0
3 years ago
Read 2 more answers
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