Hm I’m confused, if you mean what are they weighting, it’s they :)
Answer:
2.1 kg of water
Explanation:
Step 1: Given data
- Moles of lithium bromide (solute): 4.3 moles
- Molality of the solution (m): 2.05 m (2.05 mol/kg)
- Mass of water (solvent): ?
Step 2: Calculate the mass of water required
Molality is equal to the moles of solute divided by the kilograms of solvent.
m = moles of solute/kilograms of solvent
kilograms of solvent = moles of solute/m
kilograms of solvent = 4.3 mol /(2.05 mol/kg) = 2.1 kg
The percentage composition of CF4 is %C = 13.64% and %F = 86.36%
The solution are as follows:
Molar mass of CF4 = 88
<span>molar mass of C = 12 </span>
<span>molar mass of F = 4x19 = 76 </span>
<span>% C = 12/88 x 100 = 13.64% </span>
<span>% F = 76/88 x 100 = 86.36%</span>